【发布时间】：2017-01-04 18:17:09
【问题描述】：
我做错了什么？我无法理解。如果有人知道如何找出哪个 Sea Trip 的销售额最高[门票总和最大]，然后我该如何显示它 - 你会注意到它应该在源代码中的位置。我一直在尝试，但我再也做不到了。在过去的 7-8 小时内，我没有在笔记本电脑前移动过。需要帮助。
#include<iostream>
#include<fstream>
#include<string>
#include<cstdlib>
using namespace std;
struct trip
{
int day; //day of Sea Trip
int fln; //No. of Sea Trip
char name[14]; //Ship name
char capname[14]; // Captain Name
char destination[14]; // Destination
int br1; // No. pass in 1 class
int br2; // No. pass in 2 class
float price1; // Ticket price 1 class
float price2; // Ticket price 2 class
float sum; // Sum of sold tickets
};
fstream seatrips;
int add_trip(trip trip[]) //adding sea trips
{
int n;
seatrips.open("SeaTrips.txt", ios::out);
if (seatrips.fail())
{
cout << "Opening file had no success";
exit(1);
}
cout << "Enter the number of Sea Trips (max 25): ";
do
{
cin >> n;
} while (n < 0 || n > 25);
for (int i = 0; i < n; i++)
{
cout << "Enter the day of the trip (1-31) : ";
do{
cin >> trip.day;
} while (trip.day < 1 || trip.day > 31);
seatrips << trip.day << endl;
cout << "Sea Trip Number : ";
cin >> trip.fln;
seatrips << trip.fln << endl;
cout << "Ship name : ";
cin >> trip.name;
seatrips << trip.name << endl;
cout << "Captain name : ";
cin >> trip.capname;
seatrips << trip.capname << endl;
cout << "Destination : ";
cin >> trip.destination;
seatrips << trip.destination << endl;
cout << "Number of passengers in 1. class : ";
cin >> trip.br1;
seatrips << trip.br1 << endl;
cout << "Number of passengers in 2.class : ";
cin >> trip.br2;
seatrips << trip.br2 << endl;
cout << "Ticket price 1. class : ";
do{
cin >> trip.price1;
seatrips << trip.price1 << endl;
} while (trip.price1 < 1);
cout << "Ticket price 2. class : ";
do{
cin >> trip.price2;
seatrips << trip.price2 << endl;
} while (trip.price2 < 1);
trip.sum = trip.br1 * trip.price1 + trip.br2 * trip.price2;
seatrips << trip.sum;
cout << endl << endl;
}
seatrips.close();
return n;
}
void edit(trip trip[], int n) //editing pass. info
int t_fln; //temp sea trip number
seatrips.open("SeaTrips.txt", ios::out);
seatrips.seekg(0);
if (seatrips.fail())
{
cout << "Unable to open SeaTrips file";
exit(1);
}
cout << "Enter the number of the sea trip u want to edit: ";
cin >> t_fln;
for (int i = 0; i < n; i++)
{
seatrips >> trip.day;
seatrips >> trip.fln;
seatrips >> trip.name;
seatrips >> trip.br1;
seatrips >> trip.br2;
seatrips >> trip.price1;
seatrips >> trip.price2;
seatrips >> trip.sum;
if (t_fln == trip.fln)
{
cout << "Add new number of ppl in 1. class : ";
cin >> trip.br1;
seatrips << trip.br1 << endl;
cout << "Add new number of ppl in 2. class : ";
cin >> trip.br2;
seatrips << trip.br2 << endl;
}
}
seatrips.close();
}
void look(trip trip[], int n) //search by ship name, and list of all trips
int choice2, flag = 0;
string t_name;
seatrips.open("SeaTrips.txt", ios::in);
seatrips.seekg(0);
if (seatrips.fail())
{
cout << "Unable to open";
exit(1);
}
do{
cout << endl << "Choose..." << endl;
cout << "1. Find a Sea Trip by entered Ship Name." << endl;
cout << "2. List of all Sea Trips" << endl;
cout << "3. Show Sea Trip with Maximum Sold Tickets" << endl;
cout << "4. Exit" << endl;
cout << "Choice: ";
cin >> choice2;
switch (choice2)
{
case 1:{cout << "Enter info about the wanted Sea Trip..." << endl;
cout << "Ship Name: ";
cin >> t_name;
for (int i = 0; i < n; i++)
{
seatrips >> trip.day;
seatrips >> trip.fln;
seatrips >> trip.name;
seatrips >> trip.capname;
seatrips >> trip.destination;
seatrips >> trip.br1;
seatrips >> trip.br2;
seatrips >> trip.price1;
seatrips >> trip.price2;
seatrips >> trip.sum;
if (t_name == trip.name)
{
cout << "Day: " << trip.day << endl;
cout << "Number of Sea Trip: " << trip.fln << endl;
cout << "Ship name : " << trip.name << endl;
cout << "Name of captain: " << trip.capname << endl;
cout<< "Destination: " << trip.destination << endl;
cout << "Number of passengers in 1. class: " << trip.br1 << endl;
cout << "Ticket price 1. class " << trip.price1 << endl;
cout << "Number of passengers in 2. class: " << trip.br2 << endl;
cout << "Ticket price 2. class " << trip.price2 << endl;
cout << "Sum of sold tickets: " << trip.sum << endl;
cout << endl;
flag++;
}
} break; }
case 2:
for (i = 0; i < n; i++)
{
seatrips >> trip.day;
seatrips >> trip.fln;
seatrips >> trip.name;
seatrips >> trip.capname;
seatrips >> trip.destination;
seatrips >> trip.br1;
seatrips >> trip.br2;
seatrips >> trip.price1;
seatrips >> trip.price2;
seatrips >> trip.sum;
cout << "Day: " << trip.day << endl;
cout << "Number of Sea Trip: " << trip.fln << endl;
cout << "Ship Name: " << trip.name << " Captain Name " << trip.capname << " Destination " << trip.destination << endl;
cout << "Number of ppl 1. class : " << trip.br1 << endl;
cout << "Ticket price 1. class: " << trip.price1 << endl;
cout << "Number of ppl 2. class: " << trip.br2 << endl;
cout << "Ticket price 2. class: " << trip.price2 << endl;
cout << "Sum of sold tickets: "<< trip.sum << endl; }
} break; }
case 3:
/* max sales function
*
* Trip's sum is the largest one
* And display the Sea Trip here.
*
*/
} while (choice2 != 4);
seatrips.close();
}
void main()
{
setlocale(LC_ALL, "Bulgarian");
int choice1;
int n;
trip trip[25];
do
{
cout << "Menu..." << endl;
cout << "1. Adding and saving to file Sea Trips data [deletes any existing]" << endl;
cout << "2. Editing content" << endl;
cout << "3. Search and look up" << endl;
cout << "4. End" << endl;
cout << "Enter your choice: ";
cin >> choice1;
switch (choice1)
{
case 1:n = add_trip(trip); break;
case 2: edit(trip, n); break;
case 3:look(trip, n);
}
} while (choice1 != 4);
}
【问题讨论】：
-
请描述这段代码是如何不起作用的，并且只发布最少量的代码来重现它。请参阅：什么是minimal reproducible example
-
“过去 7-8 小时内没有在笔记本电脑前移动。”您会惊讶于多久离开电脑去散步或做一些其他非电脑活动会有所帮助。
-
我强烈建议在您的
struct中重载operator>>。这将简化您的代码。在 StackOverflow 上已经有很多关于如何做到这一点的示例。 -
另外，使用
std::string而不是字符数组。std::string类型允许使用运算符 、==、!= 等。对于字符数组，一个常见的错误是比较两个指针，而不是它们指向的目标。见strcmp。 -
更喜欢使用
std::vector而不是数组。std::vector更容易传递给函数并维护容量和大小属性。使用数组，您需要传递数组及其容量。通过引用或常量引用传递std::vector。