【发布时间】:2014-01-22 21:56:52
【问题描述】:
全部。
我想编写一个 Jeopardy 游戏,它从文件中读取游戏的问题、答案、类别和问题难度级别,并根据从文件中检索到的数据生成问题板。但是,我坚持如何理解文件中的数据。
这是我目前得到的:
我的输入文件格式如下:
category
difficulty
question
answer
category
difficulty
question
answer
等等等等。可以有任意数量的类别 - 游戏将随机选择其中的 6 个。有 5 个难度级别 (0-4) 来表示原始 Jeopardy 游戏的“美元增量”,将由它们各自的整数 (0-4) 表示。接下来,当然是一个问题和一个答案。示例输入文件可能如下所示:
Star Trek
0
This is the vessel that explores the galaxy.
What is the Enterprise?
Star Wars
2
These guys always miss.
What are the storm troopers?
等等等等。如您所见,类别可以按任何顺序显示,难度级别也可以。我的问题是设计一种处理这些事情的算法。
我开始考虑将我的问题和答案放在二维数组中:第一个问题将占用单元格 [0][0],第一个答案将占用单元格 [0][1],下一个问题将占用单元格 [0][1]问题将占据单元格 [1][0],下一个答案 [1][1] 等。接下来,按难度排序,我想象了一个 3D 数组:由问题和答案组成的多个 2D 数组除以难度级别.最后,我发现通过增加一个维度并制作一个 4D 数组,我可以按类别对我的难度级别进行排序。这样的数组将首先给我所有类别,然后是每个类别的所有难度级别,然后是每个类别中每个难度级别的所有问题和答案。然后将数组传递给实际使用排序数据的不同函数。
听起来它会起作用,对吧?好。我正在努力制作一种将所有内容放在正确位置的算法。我以前从未使用过大于 2D 的数组,因此 4D 数组的概念对我来说相当难以理解。我将在下面粘贴我当前的代码以供所有人阅读和评论,我热切地等待任何和所有建议。如有必要,我可以更改文件的格式,但这种 4 行组织方法是我想出的唯一方法。
void oldReadFromFile(std::string dataArray[][5][30][4], int length)
{
/*****************
The input file must be formatted as follows:
Category //capitalization counts
Dificulty //as an integer 0-4
Question
Answer
Category //capitalization counts
Dificulty //as an integer 0-4
Question
Answer
etc.
*****************/
std::ifstream inFile;
std::string category;
std::string dificulty;
std::string question;
std::string answer;
int numOfQuestions[30][5] = {0};
int numOfCategories = 0;
bool alreadyHere;
inFile.open("JeopardyData.txt");
//Determine question category
while (!inFile.eof() && numOfCategories < length) {
std::getline(inFile, category);
std::getline(inFile, dificulty);
std::getline(inFile, question);
std::getline(inFile, answer);
//inFile.get();
alreadyHere = false;
for (int i = 0; i < numOfCategories; i++)
{
if (category == dataArray[i][0][0][0]) //If the category already exists...
{
alreadyHere = true;
if (dificulty == "zero" || dificulty == "Zero" || dificulty == "0") //Determine the dificulty
{
dataArray[i][0][numOfQuestions[i][0]][1] = question;
dataArray[i][0][numOfQuestions[i][0]][2] = answer;
numOfQuestions[i][0]++;
}
else if (dificulty == "one" || dificulty == "One" || dificulty == "1")
{
dataArray[i][1][numOfQuestions[i][1]][1] = question;
dataArray[i][1][numOfQuestions[i][1]][2] = answer;
numOfQuestions[i][1]++;
}
else if (dificulty == "two" || dificulty == "Two" || dificulty == "2")
{
dataArray[i][2][numOfQuestions[i][2]][1] = question;
dataArray[i][2][numOfQuestions[i][2]][2] = answer;
numOfQuestions[i][2]++;
}
else if (dificulty == "three" || dificulty == "Three" || dificulty == "3")
{
dataArray[i][3][numOfQuestions[i][3]][1] = question;
dataArray[i][3][numOfQuestions[i][3]][2] = answer;
numOfQuestions[i][3]++;
}
else if (dificulty == "four" || dificulty == "Four" || dificulty == "4")
{
dataArray[i][4][numOfQuestions[i][4]][1] = question;
dataArray[i][4][numOfQuestions[i][4]][2] = answer;
numOfQuestions[i][4]++;
}
else { std::cout << "Bad dificulty detected in input file!\n"; }
}
}
if (!alreadyHere) //If the category DOESN'T exist yet, make it.
{
for (int i = 0; i < 5; i++)
{
dataArray[numOfCategories][i][0][0] = category;
}
if (dificulty == "zero" || dificulty == "Zero" || dificulty == "0") //Determine the dificulty
{
dataArray[numOfCategories][0][numOfQuestions[numOfCategories][0]][1] = question;
dataArray[numOfCategories][0][numOfQuestions[numOfCategories][0]][2] = answer;
numOfQuestions[numOfCategories][0]++;
}
else if (dificulty == "one" || dificulty == "One" || dificulty == "1")
{
dataArray[numOfCategories][1][numOfQuestions[numOfCategories][1]][1] = question;
dataArray[numOfCategories][1][numOfQuestions[numOfCategories][1]][2] = answer;
numOfQuestions[numOfCategories][1]++;
}
else if (dificulty == "two" || dificulty == "Two" || dificulty == "2")
{
dataArray[numOfCategories][2][numOfQuestions[numOfCategories][2]][1] = question;
dataArray[numOfCategories][2][numOfQuestions[numOfCategories][2]][2] = answer;
numOfQuestions[numOfCategories][2]++;
}
else if (dificulty == "three" || dificulty == "Three" || dificulty == "3")
{
dataArray[numOfCategories][3][numOfQuestions[numOfCategories][3]][1] = question;
dataArray[numOfCategories][3][numOfQuestions[numOfCategories][3]][2] = answer;
numOfQuestions[numOfCategories][3]++;
}
else if (dificulty == "four" || dificulty == "Four" || dificulty == "4")
{
dataArray[numOfCategories][4][numOfQuestions[numOfCategories][4]][1] = question;
dataArray[numOfCategories][4][numOfQuestions[numOfCategories][4]][2] = answer;
numOfQuestions[numOfCategories][4]++;
}
else { std::cout << "Bad dificulty detected in input file!\n"; }
numOfCategories++;
}
}
}
【问题讨论】:
-
不要使用大维数组,因为它很难读取意图并且容易出错。将 Question/Answer 封装到一个类 (
Question) 中,该类同时存储vector(或数组,因为一个类别中只有 5 个问题)Questions -
TL;DR;简短的总结: 使用
std::vector或std::array而不是c 样式的数组,这将使生活更轻松。 注意二维float数组的等价物是std::vector<std::vector<float> >!可能出于您的需要,使用一些std::map<>容器更适合让您的 4 维问题域正确。 -
你总是可以将难度转换为小写,这样你就不需要同时检查大小写,如果它是一个数字值也不会有害,它也会像ZeRo zErO一样支持等等。
-
遗憾的是,我从未听说过类或向量。我会用谷歌搜索他们并回复你们。
标签: c++ arrays algorithm file sorting