【发布时间】:2016-04-08 03:33:47
【问题描述】:
我一直在尝试制作一个动态数组。我的主要方法调用 push_back() 将整数添加到数组中 50 次。如果数组的大小需要加倍,则 push_back() 方法调用 grow_if_needed() 方法。 size() 方法返回数组的当前容量。 toString 方法用于将数组打印为字符串。我在 grow_if_needed() 方法结束时不断收到此错误。
#include <string>
class ArrayList
{
private:
static int capacity;
static int count;
public:
int& operator [](int i);
int *arrayPtr = new int[1];
ArrayList();
int * push_back(int m);
int * grow_if_needed();
int * erase(int m);
int size();
std::string toString();
};
#include "ArrayList.h"
using namespace std;
int ArrayList::capacity = 1;
int ArrayList::count = 0;
int & ArrayList::operator[](int i)
{
return arrayPtr[i];
}
ArrayList::ArrayList()
{
arrayPtr[0] = 0;
}
int * ArrayList::push_back(int m)
{
if (count == size()) {
grow_if_needed();
}
for (int i = size() - 1; i >= 0; i--) {
arrayPtr[i + 1] = arrayPtr[i];
}
arrayPtr[0] = m;
count++;
return arrayPtr;
}
int * ArrayList::grow_if_needed() {
int k;
capacity = size() * 2;
int * tempArray = new int[capacity];
for (k = 0; k < count; k++) {
tempArray[k] = arrayPtr[k];
}
while (k != capacity) {
tempArray[k] = 0;
k++;
}
delete [] arrayPtr;
arrayPtr = tempArray;
return arrayPtr;
}
int ArrayList::size()
{
return capacity;
}
string ArrayList::toString()
{
string num = "";
for (int i = 0; i <= size() - 1; i++) {
num += std::to_string(arrayPtr[i]) + " ";
}
return num;
}
【问题讨论】:
标签: c++ arrays visual-studio c++11 dynamic