【发布时间】:2021-01-10 02:49:52
【问题描述】:
我知道这是一个简单的问题解决方案,但我仍然无法弄清楚。我正在尝试通过调用函数将输入打印到数组中,但它不起作用。帮我。下面是代码。 main.cpp 和 groovy.h。供您参考,我是编程新手
这是我得到的输出
//main.cpp
#include <iostream>
#include "groovy.h"
#include <string>
#include <iomanip>
using namespace std;
void displayInventory(const groovy[], int);
int main() {
int s;
const int size = 20;
groovy car[size];
/*= {
groovy("M01", "Mazda CX5", 132403.00),
groovy("M02", "Mazda CX3", 126829.00),
groovy("M03", "Mazda 6 Grand Touring", 208408.00),
groovy("M04", "Mazda CX8", 173038.00),
};
cout<<"\nList of available car : \n"<<endl;
displayInventory(car, size);
*/
string code, model;
double price;
cout<<"\nPlease enter model details :- "<<endl;
cout<<"Model code : ";
cin>>code;
cout<<"Model name : ";
cin>>model;
cout<<"Model price : ";
cin>>price;
car[size].storeInfo(code, model, price);
displayInventory(car, size);
return 0;
}
void displayInventory(const groovy object[], int size){
for (int i = 0; i < size; i++){
cout<<setw(5)<<left<<object[i].getCode()
<<setw(28)<<left<<object[i].getModel()
<<"RM "<<right<<object[i].getPrice()<<endl;
}
}
//groovy.h
#include <iostream>
#include <iomanip>
#include <string>
using namespace std;
class groovy{
private:
string modelCode;
string model;
double price;
public:
groovy(){
modelCode = "XXX";
model = " ";
price = 0.0;
}
groovy(string c,string m, double p){
modelCode = c;
model = m;
price = p;
}
void storeInfo(string c,string m, double p) {
modelCode = c;
model = m;
price = p;
}
string getCode() const {
string code = modelCode;
return code;
}
string getModel() const {
string m = model;
return m;
}
double getPrice() const {
double p = price;
return price;
}
};
【问题讨论】:
-
预期输出是什么?
-
您可能想使用
std::vector。