实时将控制台输出重定向到 pyqt5 gui

Question

我想使用 PyQt5 在 gui 中实时重定向 python 程序的控制台输出

我的意思是，在 python 程序执行的每个输出中，gui 都会立即显示此输出

我使用的代码只在完成整个程序后显示日志，并没有解决实时问题

你能帮我吗

在我的代码下面：

from PyQt5 import QtGui,QtCore
from PyQt5 import uic
from PyQt5.QtWidgets import *
from PyQt5.QtCore import *
from PyQt5 import QtGui
from PyQt5.QtGui import QPixmap

class gui(QMainWindow):
    def __init__(self):
        super(gui, self).__init__()
        self.initUI()

    def dataReady(self):
        cursor = self.output.textCursor()
        cursor.movePosition(cursor.End)
        cursor.insertText(str(self.process.readAll()))
        self.output.ensureCursorVisible()

    def callProgram(self):
        # run the process
        # `start` takes the exec and a list of arguments
        self.process.start('python',['Robot.py'])

    def initUI(self):
        # Layout are better for placing widgets
        layout =  QHBoxLayout()
        self.runButton =  QPushButton('Run')
        self.runButton.clicked.connect(self.callProgram)

        self.output =  QTextEdit()
        self.setGeometry(100, 60, 1000, 800)
        layout.addWidget(self.output)
        layout.addWidget(self.runButton)

        centralWidget =  QWidget()
        centralWidget.setLayout(layout)
        self.setCentralWidget(centralWidget)

        # QProcess object for external app
        self.process = QtCore.QProcess(self)
        # QProcess emits `readyRead` when there is data to be read
        self.process.readyRead.connect(self.dataReady)

        # Just to prevent accidentally running multiple times
        # Disable the button when process starts, and enable it when it finishes
        self.process.started.connect(lambda: self.runButton.setEnabled(False))
        self.process.finished.connect(lambda: self.runButton.setEnabled(True))


#Function Main Start
def main():
    app =QApplication(sys.argv)
    ui=gui()
    ui.show()
    sys.exit(app.exec_())
#Function Main END

if __name__ == '__main__':
    main() ```

Answer 1

当您将 python 输出重定向到文件或管道时，出于性能原因，它会被缓冲。您需要使用-u cli 参数运行脚本或刷新每个打印输出，如下所示：print(something, flush=True)。详情请见this question。

self.process.start('python',['-u','Robot.py'])

Answer 2

这里的完整解决方案，感谢@mugiseybrows 和@eyllanesc

它解决了两个问题：第一个是在 gui 中重定向 python 程序的输出，第二个是在一个独立的行中显示每个输出

import sys
from PyQt5 import QtGui,QtCore
from PyQt5 import uic
from PyQt5.QtWidgets import *
from PyQt5.QtCore import *
from PyQt5 import QtGui
from PyQt5.QtGui import QPixmap

class gui(QMainWindow):
    def __init__(self):
        super(gui, self).__init__()
        self.initUI()

    def dataReady(self):
        cursor = self.output.textCursor()
        cursor.movePosition(cursor.End)
        #cursor.insertText(str(self.process.readAll()))
        cursor.insertText(self.process.readAll().data().decode())
        self.output.ensureCursorVisible()

    def callProgram(self):
        # run the process
        # `start` takes the exec and a list of arguments
        self.process.start('python',['-u','Robot.py'])

    def initUI(self):
        # Layout are better for placing widgets
        layout =  QHBoxLayout()
        self.runButton =  QPushButton('Run')
        self.runButton.clicked.connect(self.callProgram)

        self.output =  QTextEdit()
        self.setGeometry(100, 60, 1000, 800)
        layout.addWidget(self.output)
        layout.addWidget(self.runButton)

        centralWidget =  QWidget()
        centralWidget.setLayout(layout)
        self.setCentralWidget(centralWidget)

        # QProcess object for external app
        self.process = QtCore.QProcess(self)
        # QProcess emits `readyRead` when there is data to be read
        self.process.readyRead.connect(self.dataReady)

        # Just to prevent accidentally running multiple times
        # Disable the button when process starts, and enable it when it finishes
        self.process.started.connect(lambda: self.runButton.setEnabled(False))
        self.process.finished.connect(lambda: self.runButton.setEnabled(True))


#Function Main Start
def main():
    app =QApplication(sys.argv)
    ui=gui()
    ui.show()
    sys.exit(app.exec_())
#Function Main END

if __name__ == '__main__':
    main()