如何将此信息存储在qt中？数组列表？

Question

这里有新蜜蜂。 如果有类似的问题，我很抱歉，但我什至不知道如何正确提问。问题是，我必须为大学做一些项目，我现在被困住了。 我通过 udp 获取信息，需要存储产量信息以传递给对象（汽车坐标） 我必须为 20 个对象做这件事，因此它要复杂得多。 我有这个代码，它应该作为我的教授工作。告诉我，但我必须自己弄清楚如何存储它。 试过 QList 和 QMap 但我不知道怎么可能有

anArray[num].posX=somenumber;

所以我必须将每辆车的坐标存储为 car1.x、car1.y、car1z，然后循环计数增加； car2.x 等等。

我不知道我的问题或我想问的是否足够清楚，但请多多包涵

while(mSocket->hasPendingDatagrams()){
        QByteArray datagram;
        QHostAddress crrAddress;
        quint16 crrPort;
        datagram.resize( int(mSocket->pendingDatagramSize()) );
        mSocket->readDatagram(datagram.data(), datagram.size(), &crrAddress, &crrPort);             
        double* resultList = new double[(datagram.size() / int(sizeof(double))) ];

        memcpy(&resultList[0], datagram.data(), size_t(datagram.size()));

        for(quint16 count = 0; (count) < mVehicleCount; count++) {
            mVehicleMap[mArrayOffset + count].ID = int16_t(resultList[7 + 11 * count]);
            mVehicleMap[mArrayOffset + count].pose.position.x = resultList[(1 + 11 * count)];
            mVehicleMap[mArrayOffset + count].pose.position.y = resultList[(2 + 11 * count)];
            mVehicleMap[mArrayOffset + count].pose.position.z = resultList[(3 + 11 * count)];
            mVehicleMap[mArrayOffset + count].pose.orientation.x = resultList[(6 + 11 * count)];
        }
        delete[] resultList;

Answer 1

您可以使用QList 或QVector 类来实现您的目标（Qt 文档：QList、QVector）。

QVector 的简单示例：

    struct Vehicle
    {
        qint16 ID_;
        double position_x_;
        double position_y_;
        double position_z_;
        double orintation_x_;
    };

    ...

    QVector<Vehicle> vehicles(maxVehicleCount);  // maxVehicalCount - you variable

    ...

    while(mSocket->hasPendingDatagrams()){
            QByteArray datagram;
            QHostAddress crrAddress;
            quint16 crrPort;
            datagram.resize( int(mSocket->pendingDatagramSize()) );
            mSocket->readDatagram(datagram.data(), datagram.size(), &crrAddress, &crrPort);             
            double* resultList = new double[(datagram.size() / int(sizeof(double))) ];

            memcpy(&resultList[0], datagram.data(), size_t(datagram.size()));

            for(quint16 count = 0; (count) < mVehicleCount; count++) {
                vehicles[mArrayOffset + count].ID_ = qint16(resultList[7 + 11 * count]);
                vehicles[mArrayOffset + count].position_x_ = resultList[(1 + 11 * count)];
                vehicles[mArrayOffset + count].position_y_ = resultList[(2 + 11 * count)];
                vehicles[mArrayOffset + count].position_z_ = resultList[(3 + 11 * count)];
                vehicles[mArrayOffset + count].orintation_x_ = resultList[(6 + 11 * count)];
            }
            delete[] resultList;
    }

您也可以使用QMap 类（Qt 文档：QMap）：

    struct Vehicle
    {
        qint16 ID_;
        double position_x_;
        double position_y_;
        double position_z_;
        double orintation_x_;
    };

    ...

    QMap<qint16, Vehicle*> vehicleMap;

    ...

    while(true/*mSocket->hasPendingDatagrams()*/){
            QByteArray datagram;
            QHostAddress crrAddress;
            quint16 crrPort;
            datagram.resize( int(mSocket->pendingDatagramSize()) );
            mSocket->readDatagram(datagram.data(), datagram.size(), &crrAddress, &crrPort);             
            double* resultList = new double[(datagram.size() / int(sizeof(double))) ];

            memcpy(&resultList[0], datagram.data(), size_t(datagram.size()));

            for(quint16 count = 0; (count) < mVehicleCount; count++) {
                Vehicle* vehicle = new Vehicle();
                vehicle.ID_ = qint16(resultList[7 + 11 * count]);
                vehicle.position_x_ = resultList[(1 + 11 * count)];
                vehicle.position_y_ = resultList[(2 + 11 * count)];
                vehicle.position_z_ = resultList[(3 + 11 * count)];
                vehicle.orintation_x_ = resultList[(6 + 11 * count)];
                vehicleMap.insert(vehicle.ID_, vehicle);
            }
            delete[] resultList;
    }