创建用于计算不同车辆的不同停车费用的 if else 程序时遇到问题

Question

我无法使此代码正常工作。我刚刚学习了这个内容（if else 语句），并且必须通过创建一个计算每个不同车辆的停车成本的程序来实现它。 c 用于汽车（每小时 2 美元），b 用于公共汽车（每小时 3 美元），t 用于卡车（每小时 4 美元）。这是在使用 dev-c++ 编译器的 c 编程中。

感谢所有反馈，提前感谢您！

#include <stdio.h>

//declaration
char parkingCharge (int pc);
int pc;
int h, total, c, b, t;
char v;

int main (void)
{	
//statements

	printf ("Enter type of vehicle (c for car, ");
	printf ("b for bus, or t for truck): ");
	scanf ("%c", &v);
	
	printf ("How long did you park: ");
	scanf ("%d", &h);
	
	total = pc;
	printf ("Your total is: %d", total);

return 0;
}

char parkingCharge (int pc)
{
//statements

	if (v == c){
	   pc = 2 * h;
    }
    else if (v == b){
	   pc = 3 * h;
    }
    else if (v == t){
	   pc = 4 * h;
    }
return total;
}

Answer 1

#include <stdio.h>

//declaration
int parkingCharge (char v, int h);
int h;
char v;

int main (void)
{
//statements

        printf ("Enter type of vehicle (c for car, ");
        printf ("b for bus, or t for truck): ");
        scanf ("%c", &v);

        printf ("How long did you park: ");
        scanf ("%d", &h);
        // You forgot to call the function parkingCharge.
        int total = parkingCharge(v, h);
        printf ("Your total is: %d\n", total);

return 0;
}
// parkingCharge should return an int value and you could pass
// v and h as parameters.
int parkingCharge (char v, int h)
{
    int pc;
    // Remember when you compare a variable with a constant char, you
    // put the constant char value between ''.
    if (v == 'c'){
           pc = 2 * h;
    }
    else if (v == 'b'){
           pc = 3 * h;
    }
    else if (v == 't'){
           pc = 4 * h;
    }
    return pc;
}