将短形式数字转换为单词 Python

Question

在更改数字输入并将其转换为短形式单词方面寻求帮助：

for instance 4,000,000,000 -> 4 Trillion, 
ones = ["", "one ","two ","three ","four ", "five ", "six ","seven ","eight ","nine "]
tens = ["ten ","eleven ","twelve ","thirteen ", "fourteen ", "fifteen ","sixteen ","seventeen ","eighteen ","nineteen "]
twenties = ["","","twenty ","thirty ","forty ", "fifty ","sixty ","seventy ","eighty ","ninety "]
thousands = ["","thousand ","million ", "billion ", "trillion ", "quadrillion ", "quintillion ", "sextillion ", "septillion ","octillion ", "nonillion ", "decillion ", "undecillion ", "duodecillion ", "tredecillion ", "quattuordecillion ", "quindecillion", "sexdecillion ", "septendecillion ",  "octodecillion ", "novemdecillion ", "vigintillion "]

def wordNumber(number):
    number = int(number)  

number = str(input("Enter the digits: "))    
print(wordNumber(number))

我完全不知道下一步该去哪里，而且我查看了很多在线程序，它们用完整的数字 (10)--> 10 来做精确的事情。

Answer 1

Humanize 库将为您做到这一点：

>>> humanize.intword(12345591313)
'12.3 billion'

Answer 2

如果您需要手动执行此操作，这里是一种方法的部分示例。

def f(number):
    ones    =   [
                    "",
                    "one",
                    "two",
                    "three",
                    "four",
                    "five",
                    "six",
                    "seven",
                    "eight",
                    "nine",
                ]
    teens   =   {
                    10:"ten",
                    11:"eleven",
                    12:"twelve",
                    13:"thirteen",
                    14:"fourteen",
                    15:"fifteen",
                    16:"sixteen",
                    17:"seventeen",
                    18:"eighteen",
                    19:"nineteen",
                }
    tens    =   [
                    "",
                    "teen",
                    "twenty",
                    "thirty",
                    "fourty",
                    "fifty",
                    "sizty",
                    "seventy",
                    "eighty",
                    "ninety",
                ]
    hundred =   [ "%shundred" % one for one in ones ]
    place_value   = {1:ones,2:tens,3:hundred}
    number_string = ""
    number        = list(str(number))
    number.reverse()
    number        = [(place+1, int(digit)) for place, digit in enumerate(number)]
    number.reverse()
    number_iter = number.__iter__()
    for place, digit in number_iter:
        print place, digit
        if place == 2 and digit == 1:
            place, digit = number_iter.next()
            number_string += teens[10 + digit]
        else:
            number_string += place_value[place][digit]
        print number_string

Answer 3

这需要很多代码。你可以这样做： https://stackoverflow.com/a/19506803/3260314

或者只使用模块。示例：num2words

>>> from num2words import num2words
>>> num2words(42)
forty-two
>>> num2words(42, ordinal=True)
forty-second
>>> num2words(42, lang='fr')
quarante-deux