【发布时间】:2020-01-03 16:04:30
【问题描述】:
我想创建一个 QApplication,然后使用键盘快捷键退出。然后python脚本应该调用另一个QApplication。
我目前的问题是当第二个 QApplication 即将运行时出现此错误:
app2 = QApplication()
RuntimeError: Please destroy the QApplication singleton before creating a new QApplication instance.
我有以下结构:
| main.py
| Q1.py
| Q2.py
这是 main.py:
import Q1 as record
import Q2 as display
def main():
record.main()
display.main()
if __name__ == "__main__":
main()
这是造成问题的第一季度:
import sys
from PySide2 import QtWidgets as qtw
from PySide2 import QtGui as qtg
from PySide2 import QtCore as qtc
from PySide2 import QtMultimedia as qtmm
class MainWindow(qtw.QMainWindow):
def __init__(self):
super().__init__()
#Create Window layout with a sound widget
soundboard = qtw.QWidget()
soundboard.setLayout(qtw.QGridLayout())
self.setCentralWidget(soundboard)
sw = SoundWidget()
soundboard.layout().addWidget(sw)
#Window Dimensions
self.setSizePolicy(qtw.QSizePolicy.Expanding, qtw.QSizePolicy.MinimumExpanding)
# Code ends here
self.show()
class SendOrderButton(qtw.QPushButton):
button_stylesheet = 'background-color: blue; color: white;'
def __init__(self):
super().__init__('Send Order')
self.setSizePolicy(qtw.QSizePolicy.Expanding, qtw.QSizePolicy.Expanding)
self.setStyleSheet(self.button_stylesheet)
#self.clicked.connect(qtc.QCoreApplication.instance().quit)
def press_button(self):
if self.isEnabled():
self.setEnabled(False)
self.setText('Send Order')
else:
self.setEnabled(True)
self.setText('Sent')
class SoundWidget(qtw.QWidget):
def __init__(self):
super().__init__()
self.setLayout(qtw.QGridLayout())
#Send Order Button
self.sendorder_button = SendOrderButton()
self.sendorder_button.setShortcut(qtg.QKeySequence('Tab'))
self.layout().addWidget(self.sendorder_button, 5, 0, 1, 2)
self.sendorder_button.clicked.connect(qtc.QCoreApplication.instance().quit)
def main():
app = qtw.QApplication(sys.argv)
window = MainWindow()
window.show()
app.exec_()
if __name__ == '__main__':
app = qtw.QApplication(sys.argv)
window = MainWindow()
window.show()
sys.exit(app.exec_())
这是具有第二个 QApplication 的 Q2.py:
import sys
from PySide2.QtCore import (QAbstractTableModel, Slot)
from PySide2.QtWidgets import (QAction, QApplication, QMainWindow,QWidget)
class MainWindow(QMainWindow):
def __init__(self, widget):
QMainWindow.__init__(self)
# Exit QAction
exit_action = QAction("Exit", self)
exit_action.setShortcut("Ctrl+Q")
exit_action.triggered.connect(self.exit_app)
@Slot()
def exit_app(self, checked):
sys.exit()
class CustomTableModel(QAbstractTableModel):
def __init__(self, data=None):
QAbstractTableModel.__init__(self)
class Widget(QWidget):
def __init__(self):
QWidget.__init__(self)
# Getting the Model
self.model = CustomTableModel()
def main():
app2 = QApplication()
widget = Widget()
window2 = MainWindow(widget)
window2.show()
sys.exit(app2.exec_())
if __name__ == "__main__":
app = QApplication()
widget = Widget()
window = MainWindow(widget)
window.show()
sys.exit(app.exec_())
【问题讨论】:
-
第二个 QApplication 还用在什么地方?将
self.sendorder_button.clicked.connect(qtc.QCoreApplication.instance().quit)更改为self.sendorder_button.clicked.connect(self.close) -
只关闭小部件,窗口保持打开状态,脚本不继续。另一个应用程序是从 master.py 调用的,它位于不同的模块中。
-
如果您需要帮助提供 MRE,您的代码不是。为什么一定要有2个QApplication?
-
主文件是什么?是第一个代码还是第二个代码还是另一个?,因为您的问题不清楚,请更好地解释自己。
标签: python python-3.x qt pyqt pyside2