【发布时间】:2019-03-05 22:03:20
【问题描述】:
我正在尝试从启动 QQmlApplication 引擎的 python 文件中访问 FileDialog 控件,以检索文件路径属性。我已经在 .qml 文件中设置了一个信号,但是我无法通过 python 文件中的 id 访问文件对话框来设置插槽。 application.py 中的 findChild 方法返回 None。代码如下:
应用程序.py
import sys
from PySide2.QtGui import QGuiApplication
from PySide2.QtQml import QQmlApplicationEngine, QQmlFileSelector
sys_argv = sys.argv
sys_argv += ['--style', 'material']
app = QGuiApplication(sys_argv)
window = QQmlApplicationEngine()
window.load("QML/main.qml")
fileDialog = window.findChild(QQmlFileSelector, "fileDialog")
print(fileDialog)
app.exec_()
Page1.qml
import QtQuick 2.9
import QtQuick.Controls 2.2
import QtQuick.Dialogs 1.2
Page {
width: 600
height: 400
header: Label {
text: qsTr("Prepare Data")
horizontalAlignment: Text.AlignHCenter
font.pixelSize: Qt.application.font.pixelSize * 2
padding: 10
}
Button {
text: qsTr("Load data")
anchors.centerIn: parent
onClicked: fileDialog.visible = true
padding: 10
}
signal folderSelected()
FileDialog {
id: fileDialog
selectFolder: true
title: qsTr("Select the data directory")
folder: shortcuts.home
onAccepted: {
parent.folderSelected()
}
}
}
main.qml
import QtQuick 2.0
import QtQuick.Controls 2.12
import QtQuick.Controls.Material 2.12
ApplicationWindow{
visible: true
title: qsTr("Main window")
width: 1000
height: 800
Material.theme: Material.Light
Material.accent: Material.Orange
SwipeView {
id: swipeView
anchors.fill: parent
Page1 {
}
Page2 {
}
Page3 {
}
}
}
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