【发布时间】:2016-11-07 14:26:58
【问题描述】:
我一直在尝试使用 PyQt5,但我遇到了一个奇怪的问题,我无法从 python 应用程序导入 QtQuick.Dialogs。
因此,请考虑以下 QML 文件:
example.qml
import QtQuick 2.0
import QtQuick.Window 2.1
import QtQuick.Layouts 1.1
import QtQuick.Controls 1.4
import QtQuick.Controls.Styles 1.4
import QtQuick.Dialogs 1.0 // Offending line!
import DicomSorter 1.0
ApplicationWindow {
id: rootWindow
objectName: "window"
visible: true
width: 800
height: 480
title: "Test"
Component.onCompleted: {
setX(Screen.width / 2 - width / 2);
setY(Screen.height / 2 - height / 2);
}
style: ApplicationWindowStyle {
background: Rectangle {
color: "#FFFFFF"
}
}
// Login Form
Rectangle {
id: loginForm
ColumnLayout {
anchors.centerIn: parent
spacing: 25
width: 200
TextField {
id: usernameField
placeholderText: qsTr("User name")
Layout.fillWidth: true
}
TextField {
id: passwordField
placeholderText: qsTr("Password")
Layout.fillWidth: true
echoMode: TextInput.Password
}
RowLayout {
Button {
id: loginButton
text: "Log In"
Layout.fillWidth: true
onClicked: {
stackView.push(dirSelector)
}
}
Button {
id: cancelButton
text: "Cancel"
Layout.fillWidth: true
}
}
}
} // Login Form
// The main stackview component
StackView {
id: stackView
anchors.fill: parent
Component.onCompleted:
{
stackView.push(loginForm)
}
} // StackView
}
现在,我简单地从我的 python 应用程序中调用它,如下所示:
from PyQt5.QtCore import QUrl
from PyQt5.QtWidgets import QApplication
from PyQt5.QtQuick import QQuickView, QQuickWindow
from PyQt5.QtQml import qmlRegisterType, QQmlApplicationEngine
import sys
import os
app = QApplication(sys.argv)
engine = QQmlApplicationEngine(example.qml')
print "Created"
topLevel = engine.rootObjects()[0]
win = QQuickWindow(topLevel)
win.show()
app.exec_()
现在,在我的 python 2.7 和 PyQt5.6 上,这个应用程序挂起。但是,如果您将 import QtQuick.Dialogs 1.0 注释掉,它会起作用。
【问题讨论】:
-
运行带有
QML_IMPORT_TRACE=1环境变量集的应用程序,并附加输出。
标签: python qt qml qtquick2 pyqt5