QWebKit linkClicked 信号从不触发答案

【问题标题】：QWebKit linkClicked signal never firesQWebKit linkClicked 信号从不触发
【发布时间】：2011-03-21 20:08:48
【问题描述】：

import sys

from PyQt4.QtGui import *
from PyQt4.QtCore import *
from PyQt4.QtWebKit import QWebView

app = QApplication(sys.argv)
web_view = QWebView()
def url_changed(url):  print 'url changed: ', url
def link_clicked(url):  print 'link clicked: ', url
def load_started():  print 'load started'
def load_finished(ok):  print 'load finished, ok: ', ok
web_view.connect(web_view, SIGNAL("urlChanged(const QUrl&)"), url_changed)
web_view.connect(web_view, SIGNAL("linkClicked(const QUrl&)"), link_clicked)
web_view.connect(web_view, SIGNAL('loadStarted()'), load_started)
web_view.connect(web_view, SIGNAL('loadFinished(bool)'), load_finished)
web_view.load(QUrl('http://google.com'))
web_view.show()
sys.exit(app.exec_())

linkClicked 信号不起作用。其他信号有效。 Win XP 上的 Qt 4.6.2。

【问题讨论】：

标签： python qt pyqt qwebview qwebkit

【解决方案1】：

link delegation policy 必须适当设置才能发出 linkClicked 信号。

import sys

from PyQt4.QtGui import *
from PyQt4.QtCore import *
from PyQt4.QtWebKit import QWebPage, QWebView

app = QApplication(sys.argv)
web_view = QWebView()
web_view.page().setLinkDelegationPolicy(QWebPage.DelegateAllLinks)
def url_changed(url):  print 'url changed: ', url
def link_clicked(url):  print 'link clicked: ', url
def load_started():  print 'load started'
def load_finished(ok):  print 'load finished, ok: ', ok
web_view.connect(web_view, SIGNAL("urlChanged(const QUrl&)"), url_changed)
web_view.connect(web_view, SIGNAL("linkClicked(const QUrl&)"), link_clicked)
web_view.connect(web_view, SIGNAL('loadStarted()'), load_started)
web_view.connect(web_view, SIGNAL('loadFinished(bool)'), load_finished)
web_view.load(QUrl('http://google.com'))
web_view.show()
sys.exit(app.exec_())

【讨论】：