如何对具有最高特定值的哈希进行排序？

Question

我在一个名为 elem 的数组中有哈希值，我必须获得具有最高“计数”值的“类型”键。

我知道枚举器是一个很棒的知识，但我不太了解它们。

elem = [{"type"=>"dododo", "count"=>0, "name"=>"dododo's", "tip"=>"dododo's Level"},
  {"type"=>"dadada", "count"=>1203, "name"=>"dadada's", "tip"=>"dadada's Degree"},
  {"type"=>"dedede", "count"=>717, "name"=>"dedede's", "tip"=>"dedede's Degree"},
  {"type"=>"dididi", "count"=>6, "name"=>"dididi's", "tip"=>"dididi or Professional Degree"}]

我正在尝试这个：

elem.each do |i|
  i.each_with_index do |k,v|
    puts v["count"]
  end
end

但我知道我错过了一些步骤。

我知道这种“策略”相当常见，而且很重要。

Answer 1

一种方法是使用Enumerable#max_by

elem = [
  {"type"=>"dododo", "count"=>0, "name"=>"dododo's", "tip"=>"dododo's Level"},
  {"type"=>"dadada", "count"=>1203, "name"=>"dadada's", "tip"=>"dadada's Degree"},
  {"type"=>"dedede", "count"=>717, "name"=>"dedede's", "tip"=>"dedede's Degree"},
  {"type"=>"dididi", "count"=>6, "name"=>"dididi's", "tip"=>"dididi or Professional Degree"}
]

max_elem = elem.max_by {|e| e['count']}
puts max_elem['type']
# returns dadada