【发布时间】：2020-04-07 23:26:05
【问题描述】：
说明：
我使用 Homebrew 在我的 MacBook 上安装了 spark。我遵循了来自：https://www.tutorialkart.com/apache-spark/how-to-install-spark-on-mac-os/ 的指令过程。
分步过程包括安装 Java，然后是 Scala，然后是 Spark。 Java 和 Scala 安装成功。 Spark 也安装成功。
当我尝试使用以下输入命令验证 spark 安装时，我遇到了错误。
输入指令： spark-shell
预期行为：预期 Spark 在终端上启动
实际行为：我收到以下错误：
Unable to find any JVMs matching version "1.8".
WARNING: An illegal reflective access operation has occurred
WARNING: Illegal reflective access by org.apache.spark.unsafe.Platform (file:/usr/local/Cellar/apache-spark/2.4.5/libexec/jars/spark-unsafe_2.11-2.4.5.jar) to method java.nio.Bits.unaligned()
WARNING: Please consider reporting this to the maintainers of org.apache.spark.unsafe.Platform
WARNING: Use --illegal-access=warn to enable warnings of further illegal reflective access operations
WARNING: All illegal access operations will be denied in a future release
Exception in thread "main" java.lang.ExceptionInInitializerError
at org.apache.hadoop.util.StringUtils.<clinit>(StringUtils.java:80)
at org.apache.hadoop.security.SecurityUtil.getAuthenticationMethod(SecurityUtil.java:611)
at org.apache.hadoop.security.UserGroupInformation.initialize(UserGroupInformation.java:273)
at org.apache.hadoop.security.UserGroupInformation.ensureInitialized(UserGroupInformation.java:261)
at org.apache.hadoop.security.UserGroupInformation.loginUserFromSubject(UserGroupInformation.java:791)
at org.apache.hadoop.security.UserGroupInformation.getLoginUser(UserGroupInformation.java:761)
at org.apache.hadoop.security.UserGroupInformation.getCurrentUser(UserGroupInformation.java:634)
at org.apache.spark.util.Utils$$anonfun$getCurrentUserName$1.apply(Utils.scala:2422)
at org.apache.spark.util.Utils$$anonfun$getCurrentUserName$1.apply(Utils.scala:2422)
at scala.Option.getOrElse(Option.scala:121)
at org.apache.spark.util.Utils$.getCurrentUserName(Utils.scala:2422)
at org.apache.spark.SecurityManager.<init>(SecurityManager.scala:79)
at org.apache.spark.deploy.SparkSubmit.secMgr$lzycompute$1(SparkSubmit.scala:348)
at org.apache.spark.deploy.SparkSubmit.org$apache$spark$deploy$SparkSubmit$$secMgr$1(SparkSubmit.scala:348)
at org.apache.spark.deploy.SparkSubmit$$anonfun$prepareSubmitEnvironment$7.apply(SparkSubmit.scala:356)
at org.apache.spark.deploy.SparkSubmit$$anonfun$prepareSubmitEnvironment$7.apply(SparkSubmit.scala:356)
at scala.Option.map(Option.scala:146)
at org.apache.spark.deploy.SparkSubmit.prepareSubmitEnvironment(SparkSubmit.scala:355)
at org.apache.spark.deploy.SparkSubmit.org$apache$spark$deploy$SparkSubmit$$runMain(SparkSubmit.scala:774)
at org.apache.spark.deploy.SparkSubmit.doRunMain$1(SparkSubmit.scala:161)
at org.apache.spark.deploy.SparkSubmit.submit(SparkSubmit.scala:184)
at org.apache.spark.deploy.SparkSubmit.doSubmit(SparkSubmit.scala:86)
at org.apache.spark.deploy.SparkSubmit$$anon$2.doSubmit(SparkSubmit.scala:920)
at org.apache.spark.deploy.SparkSubmit$.main(SparkSubmit.scala:929)
at org.apache.spark.deploy.SparkSubmit.main(SparkSubmit.scala)
Caused by: java.lang.StringIndexOutOfBoundsException: begin 0, end 3, length 2
at java.base/java.lang.String.checkBoundsBeginEnd(String.java:3756)
at java.base/java.lang.String.substring(String.java:1902)
at org.apache.hadoop.util.Shell.<clinit>(Shell.java:52)
我尝试了什么：
我尝试使用以下命令更改 JAVA_HOME：
export JAVA_HOME=/usr/local/opt/java
以前的 JAVA_HOME 路径是 /opt/anaconda3。我可以看到 JAVA_HOME 已更改为 usr/local/opt/java。
我仍然收到错误消息。感谢您的回答/反馈。谢谢！！！
【问题讨论】：
-
您是否安装了较新版本的 Java？
/usr/local/opt/java/bin/java -version的结果是什么？ -
是的，作为 spark 安装的一部分，我确实安装了更新版本的 Java。奇怪...
/usr/local/opt/java/bin/java -version给了我这个：openjdk 版本“13.0.2”2020-01-14 OpenJDK 运行时环境（构建 13.0.2+8）OpenJDK 64 位服务器 VM（构建 13.0.2+8，混合模式） ，分享）。当我从默认提示中输入java -version时，我得到了这个： openjdk version "1.8.0_152-release" OpenJDK Runtime Environment (build 1.8.0_152-release-1056-b12) OpenJDK 64-Bit Server VM (build 25.152 -b12，混合模式） -
好的。现在试试
which java -
当我尝试 'which
which java我得到这个：/Users/skanda_work/opt/anaconda3/bin/java -
export JAVA_HOME=/Users/skanda_work/opt/anaconda3
标签： java macos scala apache-spark homebrew-cask