JQ 交叉引用或如何用输入的另一部分替换一个值

Question

我想解析 terraform.tfstate（使用 openstack 提供程序的地方），返回实例名称及其内部 + 浮动 IP（如果已分配）。

首先选择我们感兴趣的：

jq -r '.modules?[]|.resources[]?|select(.type == "openstack_compute_floatingip_v2", .type == "openstack_compute_instance_v2")' < terraform.tfstate

为简单起见，使用上述部分预解析示例（一个 FIP 和一个实例）：

{
  "type": "openstack_compute_floatingip_v2",
  "depends_on": [
    "openstack_networking_router_interface_v2.management"
  ],
  "primary": {
    "id": "48b039fc-a9fa-4672-934a-32d6d267f280",
    "attributes": {
      "address": "209.66.89.143",
      "fixed_ip": "10.10.10.5",
      "id": "48b039fc-a9fa-4672-934a-32d6d267f280",
      "instance_id": "597e75e8-834d-4f05-8408-e2e6e733577e",
      "pool": "public",
      "region": "RegionOne"
    },
    "meta": {},
    "tainted": false
  },
  "deposed": [],
  "provider": "provider.openstack"
}
{
  "type": "openstack_compute_instance_v2",
  "depends_on": [
    "openstack_compute_floatingip_v2.management",
    "openstack_compute_secgroup_v2.ssh_only",
    "openstack_networking_network_v2.management"
  ],
  "primary": {
    "id": "597e75e8-834d-4f05-8408-e2e6e733577e",
    "attributes": {
      "access_ip_v4": "10.10.10.5",
      "access_ip_v6": "",
      "all_metadata.%": "1",
      "all_metadata.habitat": "sup",
      "availability_zone": "nova",
      "flavor_id": "eb36e84e-17c1-42ab-b359-4380f6f524ae",
      "flavor_name": "m1.large",
      "force_delete": "false",
      "id": "597e75e8-834d-4f05-8408-e2e6e733577e",
      "image_id": "c574aeed-e47c-4fb7-9da0-75550b76ee56",
      "image_name": "ubuntu-16.04",
      "key_pair": "vault-etcd_test_tf",
      "metadata.%": "1",
      "metadata.habitat": "sup",
      "name": "ctl01",
      "network.#": "1",
      "network.0.access_network": "false",
      "network.0.fixed_ip_v4": "10.10.10.5",
      "network.0.fixed_ip_v6": "",
      "network.0.floating_ip": "",
      "network.0.mac": "02:c6:61:f9:ee:7e",
      "network.0.name": "management",
      "network.0.port": "",
      "network.0.uuid": "f2468669-e321-4eb4-9ede-003e362a8988",
      "region": "RegionOne",
      "security_groups.#": "1",
      "security_groups.1845949017": "vault-etcd_test_ssh_only",
      "stop_before_destroy": "false"
    },
    "meta": {
      "e2bfb730-ecaa-11e6-8f88-34363bc7c4c0": {
        "create": 1800000000000,
        "delete": 1800000000000,
        "update": 1800000000000
      }
    },
    "tainted": false
  },
  "deposed": [],
  "provider": "provider.openstack"
}

需要从"type": "openstack_compute_floatingip_v2" 替换.primary.attributes.address 和.fixed_ip 并从相应的.instance_id 中获取.name。

所以，比如：

{"address": "209.66.89.143",
"fixed_ip": "10.10.10.5",
"name": "ctl01"}

好吧，我在使用 walk 时想到了一个想法，但错过了如何从相应的实例 id 实际分配正确的值：

jq -r "$(cat floating.jq)" terraform.tfstate

浮动.jq：

def walk(f):
      . as $in
      | if type == "object" then
          reduce keys[] as $key
            ( {}; . + { ($key):  ($in[$key] | walk(f)) } ) | f
      elif type == "array" then map( walk(f) ) | f
      else f
      end;
.modules?[]|.resources[]?|select(.type == 
    "openstack_compute_floatingip_v2", .type == 
    "openstack_compute_instance_v2")|
    .primary|walk( if  type == "object" and .attributes.address then 
    .attributes.instance_id |= "REFERRED VALUE HERE") else . end)

Answer 1

假设这两个相关对象位于名为 two.json 的文件中。然后合并来自两个对象的信息的一种方法是使用-s 命令行选项，例如

jq -s '
  (.[0].primary.attributes | {address, fixed_ip})
  + {name: .[1].primary.attributes.name}' two.json

输出

使用您的示例输入，输出将是：

{
  "address": "209.66.89.143",
  "fixed_ip": "10.10.10.5",
  "name": "ctl01"
}