【发布时间】:2014-02-26 04:48:02
【问题描述】:
我有JSF 2.2、Primefaces 3.5、Spring、Spring Security 3.x、Hibernate 4、MySQL 网络应用程序。
我已启用Spring Security 按预期工作,但我使用<user-service/> 创建了两个具有不同角色的用户(“ROLE_USER”、“ROLE_ADMIN”)。现在我想搜索数据库中的每个用户,而不是在<user-service/> 中手动创建它们。
applicationContext.xml:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:sec="http://www.springframework.org/schema/security"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.1.xsd">
<!-- GLOABL SETTINGS -->
<context:component-scan base-package="com.infostroy.adminportal"/>
<tx:annotation-driven transaction-manager="transactionManager" proxy-target-class="true"/>
<!-- DATA SOURCE AND PERSISTENCE SETTINGS -->
<bean id="propertiesPlaceholderConfigurer" class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
<property name="locations">
<list>
<value>classpath:db.properties</value>
</list>
</property>
</bean>
<bean id="sessionFactory" class="org.springframework.orm.hibernate4.LocalSessionFactoryBean">
<property name="dataSource" ref="dmDataSource"/>
<property name="packagesToScan" value="com.infostroy.adminportal"/>
<property name="hibernateProperties">
<props>
<prop key="hibernate.dialect">${db.dialect}</prop>
<prop key="hibernate.show_sql">${db.show_sql}</prop>
<prop key="hibernate.hbm2ddl.auto">${db.hbm2ddl_auto}</prop>
<prop key="connection.pool_size">${db.pool_size}</prop>
<prop key="current_session_context_class">${db.current_session_context_class}</prop>
<prop key="org.hibernate.FlushMode">${db.flush_mode}</prop>
</props>
</property>
</bean>
<bean id="transactionManager"
class="org.springframework.orm.hibernate4.HibernateTransactionManager">
<property name="dataSource" ref="dmDataSource" />
<property name="sessionFactory" ref="sessionFactory" />
</bean>
<bean id="dmDataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close">
<property name="driverClassName" value="${db.driver}" />
<property name="url" value="${db.url}" />
<property name="username" value="${db.username}" />
<property name="password" value="${db.password}" />
<property name="maxWait" value="5000" />
<property name="initialSize" value="2" />
<property name="maxActive" value="100"/>
<property name="maxIdle" value="50"/>
<property name="minIdle" value="0"/>
</bean>
</beans>
spring-security.xml:
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/security"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:beans="http://www.springframework.org/schema/beans"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.1.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-3.1.xsd">
<http auto-config="false" use-expressions="true">
<intercept-url pattern="/protected/*" access="isAuthenticated()"/>
<form-login login-page="/login.xhtml" login-processing-url="/j_spring_security_check"
default-target-url="/protected/home.xhtml"
authentication-failure-url="/loginFailed.xhtml"/>
</http>
<authentication-manager>
<authentication-provider>
<user-service>
<user name="c" password="c" authorities="ROLE_ADMIN" />
<user name="q" password="q" authorities="ROLE_USER" />
</user-service>
</authentication-provider>
</authentication-manager>
</beans:beans>
这是创建用户表的脚本:
CREATE TABLE users (
user_id INT AUTO_INCREMENT,
first_name VARCHAR(20),
last_name VARCHAR(20),
login VARCHAR(20) NOT NULL UNIQUE,
password VARCHAR(32) NOT NULL,
role VARCHAR(20) NOT NULL,
PRIMARY KEY(user_id)
) ENGINE=InnoDB;
有谁知道如何做到这一点?每个答案都受到高度赞赏并迅速回复!
谢谢。
【问题讨论】:
标签: mysql hibernate jakarta-ee authentication spring-security