【问题标题】:Java Spring Security - The constructor Security Properties User is not definedJava Spring Security - 构造函数安全属性用户未定义
【发布时间】:2019-03-18 03:07:35
【问题描述】:

我收到此错误消息:

错误:构造函数 SecurityProperties.User(String, String, boolean, boolean, boolean, boolean, List) 是 未定义

这是我的代码:

package org.launchcode.shopcartsbh.service;

import java.util.ArrayList;
import java.util.List;

import org.launchcode.shopcartsbh.dao.AccountDAO;
import org.launchcode.shopcartsbh.entity.Account;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.security.core.GrantedAuthority;
import org.springframework.security.core.authority.SimpleGrantedAuthority;
import org.springframework.boot.autoconfigure.security.SecurityProperties.User;
import org.springframework.security.core.userdetails.UserDetails;
import org.springframework.security.core.userdetails.UserDetailsService;
import org.springframework.security.core.userdetails.UsernameNotFoundException;
import org.springframework.stereotype.Service;


@Service("userDetailsService")
public class UserDetailsServiceImpl implements UserDetailsService {

@Autowired
private AccountDAO accountDAO;

@Override
public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException {
    Account account = accountDAO.findAccount(username);
    System.out.println("Account= " + account);

    if (account == null) {
        throw new UsernameNotFoundException("User " //
                + username + " was not found in the database");
    }

    // EMPLOYEE,MANAGER,..
    String role = account.getUserRole();

    List<GrantedAuthority> grantList = new ArrayList<GrantedAuthority>();

    // ROLE_EMPLOYEE, ROLE_MANAGER
    GrantedAuthority authority = new SimpleGrantedAuthority(role);

    grantList.add(authority);

    String user = account.getUserName();
    String password = account.getEncrytedPassword();

    boolean enabled = account.isActive();
    boolean accountNonExpired = true;
    boolean credentialsNonExpired = true;
    boolean accountNonLocked = true;

****   UserDetails userDetails = (UserDetails) new User(user, password, enabled, accountNonExpired, credentialsNonExpired, accountNonLocked, grantList); 
**** this is where the error is

    return userDetails;
}

}

我想知道他们是否可以通过某种方式重写它以使其更实用?过去几天我一直在研究这个问题,但仍然没有找到解决方案。

【问题讨论】:

    标签: java hibernate authentication spring-security


    【解决方案1】:

    你输入了错误的Userclass,应该是

    import org.springframework.security.core.userdetails.User
    

    而不是

    import org.springframework.boot.autoconfigure.security.SecurityProperties.User;
    

    【讨论】:

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