我自己终于想出了这个。不过大部分功劳都属于这个blog post。
你可以使用这个方法来分解你的矩阵:
private void DecomposeMatrix(ref Matrix matrix, out Vector2 position, out float rotation, out Vector2 scale)
{
Vector3 position3, scale3;
Quaternion rotationQ;
matrix.Decompose(out scale3, out rotationQ, out position3);
Vector2 direction = Vector2.Transform(Vector2.UnitX, rotationQ);
rotation = (float)Math.Atan2((double)(direction.Y), (double)(direction.X));
position = new Vector2(position3.X, position3.Y);
scale = new Vector2(scale3.X, scale3.Y);
}
然后您可以像这样为您的叶子精灵构建一个变换矩阵:
Matrix transform =
Matrix.CreateScale(new Vector3(this.Scale, 1.0f)) *
Matrix.CreateRotationZ(this.Rotation) *
Matrix.CreateTranslation(new Vector3(this.Position, 0));
对于你的父精灵,包括原点:
Matrix transform =
Matrix.CreateTranslation(new Vector3(-this.Origin, 0)) *
Matrix.CreateScale(new Vector3(this.Scale, 1.0f)) *
Matrix.CreateRotationZ(this.Rotation) *
Matrix.CreateTranslation(new Vector3(this.position, 0));
以相反的顺序乘以堆栈中的所有矩阵。