如何从 Spring Security 上的 CustomUser 获取用户 ID

Question

ussign Spring Security，我试图从我的 CustomUserDetailsS​​ervice 上的 loadUserByUsername 方法返回的 CustomUser 实例中获取用户 ID，就像我通过身份验证获取名称 (get.Name()) 一样。感谢您的任何提示！

这就是我获取登录用户当前名称的方式：

Authentication authentication = SecurityContextHolder.getContext().getAuthentication();
String name = authentication.getName();

这是自定义用户

public class CustomUser extends User {

    private final int userID;

    public CustomUser(String username, String password, boolean enabled, boolean accountNonExpired,
                      boolean credentialsNonExpired,
                      boolean accountNonLocked,
                      Collection<? extends GrantedAuthority> authorities, int userID) {
        super(username, password, enabled, accountNonExpired, credentialsNonExpired, accountNonLocked, authorities);
        this.userID = userID;
    }
}

我的服务上的 loadUserByUsername 方法

@Override
public UserDetails loadUserByUsername(String s) throws UsernameNotFoundException {

    Usuario u = usuarioDAO.getUsuario(s);

    return new CustomUser(u.getLogin(), u.getSenha(), u.isAtivo(), u.isContaNaoExpirada(), u.isContaNaoExpirada(),
            u.isCredencialNaoExpirada(), getAuthorities(u.getRegraByRegraId().getId()),u.getId()
    );
}

Answer 1

Authentication authentication = ...
CustomUser customUser = (CustomUser)authentication.getPrincipal();
int userId = customUser.getUserId();

如果您还没有 getUserId() getter 方法，则必须添加它。