如何编译 POSIX 计时器

Question

我正在尝试在多线程程序中使用 POSIX 计时器创建超时函数 (enable_timeout)。我需要强制该函数的调用线程是接收和处理SIGALRM 信号的线程。为此，我有以下代码，它基于 man timer_create 并进行了一些修改：

void procman_enable_timeout(int msec)
{
    timer_t timerid;
    struct sigevent sev;
    struct itimerspec its;

    // Disable the signal:
    procman_sig_disable(SIGALRM);

    // Will send the signal to the calling thread.
    sev.sigev_notify = SIGEV_THREAD_ID;
    sev.sigev_notify_thread_id = syscall(SYS_gettid);
    // Signal to be sent:
    sev.sigev_signo = SIGALRM; 
    sev.sigev_value.sival_ptr = &timerid;

    // Create the timer:
    timer_create(CLOCK_REALTIME, &sev, &timerid); // Does not start it. 


    // Configure the timer to expire after the specified interval:
    its.it_value.tv_sec = (msec/1000);
    its.it_value.tv_nsec = (msec*1000000)%1000000;
    // Will not be periodic:
    its.it_interval.tv_sec = 0;
    its.it_interval.tv_nsec = 0;

    // Install and enable signal handler:
    sigalrm_catched = false;
    procman_sig_enable(SIGALRM);

    // Start timer:
    timer_settime(timerid, 0, &its, NULL);

    while(!sigalrm_catched)
        pause(); // Waits for the reception of a SIGALRM (or any other signal!)
    sigalrm_catched = false;

    // Disable signal handler:
    procman_sig_disable(SIGALRM);
}

但是，当我尝试编译它（使用-lrt 选项）时，GCC 会输出以下内容：

procman.c:137:8: error: ‘struct sigevent’ has no member named ‘sigev_notify_thread_id’
 sev.sigev_notify_thread_id = syscall(SYS_gettid);
    ^

我错过了什么？我包括了time.h 和signals.h。它不应该工作吗？

编辑：我也在使用pthread_mutex_init(&mutex, PTHREAD_MUTEX_ERRORCHECK)。 @alk 建议将 POSIX.1b 定义为包含 POSIX 计时器，但这删除了此功能。

Answer 1

要使 POSIX 计时器事件可用，定义 _POSIX_C_SOURCE 需要设置为至少 199309L：

 #define _POSIX_C_SOURCE 199309L

对于最新的 POSIX 功能，您可以尝试将其设置为 200809L，例如

#define _POSIX_C_SOURCE 200809L

有关各种可能性的详细信息，请参阅：http://man7.org/linux/man-pages/man7/feature_test_macros.7.html