【发布时间】:2018-08-03 07:48:20
【问题描述】:
无法使用控制器建议返回 Rest ApiResponse。
解决方案已实施
** 我的方法**
1)我创建了一个抛出异常的控制器。
2)全局异常处理程序将使用@ControllerAdvice 捕获异常。
3) 特定方法将返回响应为 APIResponse。
显示输出
{
"timestamp": 1519377824339,
"status": 404,
"error": "Not Found",
"exception": "java.lang.Exception",
"message": "No message available",
"path": "/test"
}
控制台的输出显示
System.out.println("此处收到异常请求");
预期输出
{
"success": false,
"message": "null Your Exception ",
"object": null
}
下面是我的代码
@RequestMapping("/test")
@RestController
public class TestController {
@Autowired
private UserService userService;
@PostMapping
ApiResponse<User> post(@RequestBody User user) throws Exception {
if(true)
throw new Exception();
return ApiResponse.success().object(userService.post(user));
}
}
@ControllerAdvice
public class GlobalExceptionHandlerController {
@ExceptionHandler(value = Exception.class)
public ApiResponse<Void> handleDefaultException(Exception exception) {
System.out.println(" Request Received Here for Exception ");
return ApiResponse.failure().message(exception.getMessage() + "Please check your Response").build();
}
}
public class ApiResponse<T> {
private boolean success;
private String message;
private T object;
public static class ResponseBuilder {
private boolean success;
private String message;
private ResponseBuilder(boolean success) {
this.success = success;
this.message = "";
}
public ResponseBuilder message(String message) {
this.message = message;
return this;
}
public <C> ApiResponse<C> object(C object) {
return new ApiResponse<C>(success, message, object);
}
public <C> ApiResponse<C> build() {
return new ApiResponse<>(success, message, null);
}
}
public static ResponseBuilder success() {
return new ResponseBuilder(true);
}
public static ResponseBuilder failure() {
return new ResponseBuilder(false);
}
private ApiResponse(boolean success, String message, T object) {
this.success = success;
this.message = message;
this.object = object;
}
public boolean isSuccess() {
return success;
}
public void setSuccess(boolean success) {
this.success = success;
}
public String getMessage() {
return message;
}
public void setMessage(String message) {
this.message = message;
}
public T getObject() {
return object;
}
public void setObject(T object) {
this.object = object;
}
}
请求网址
本地主机:6005/测试
用户正文包含
{
"name":"jalaj"
}
下面是我的 pom.xml
<parent>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-parent</artifactId>
<version>1.5.10.RELEASE</version>
<relativePath/> <!-- lookup parent from repository -->
</parent>
<dependencies>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-data-jpa</artifactId>
</dependency>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-data-mongodb</artifactId>
</dependency>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-web</artifactId>
</dependency>
<dependency>
<groupId>mysql</groupId>
<artifactId>mysql-connector-java</artifactId>
<scope>runtime</scope>
</dependency>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-test</artifactId>
<scope>test</scope>
</dependency>
</dependencies>
我只能从输出判断我的控制器没有执行。
您可以从我的 bitbucket 配置文件下载代码以查看我的代码。
https://bitbucket.org/JalajChawla/
如果我遗漏了什么,谁能指导我?
【问题讨论】:
标签: java spring-boot exception-handling aop