无法定义 Bean 类型并且 Autowired 为 Null [重复]答案

【问题标题】：Could Not Defining Bean Type and Autowired is Null [duplicate]无法定义 Bean 类型并且 Autowired 为 Null [重复]
【发布时间】：2020-11-27 14:45:03
【问题描述】：

我想在 java 中的身份验证过滤器上使用我的服务时遇到一些问题。这是我的代码

AuthenticationFilter.java

public class AuthenticationFilter extends UsernamePasswordAuthenticationFilter {

@Autowired
private AuthenticationManager authManager;

@Autowired
private UserService userService;

public AuthenticationFilter(AuthenticationManager authManager) {
    this.authManager = authManager;

    super.setFilterProcessesUrl("/api/login");
}

@Override
public Authentication attemptAuthentication(HttpServletRequest request, HttpServletResponse response)
        throws AuthenticationException {
    User user = new User();

    try {
        Object req = request.getInputStream();
        user = new ObjectMapper().readValue(request.getInputStream(), User.class);
    } catch (Exception e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

    return authManager.authenticate(new UsernamePasswordAuthenticationToken(user.getUname(), user.getPass()));

}

@Override
protected void successfulAuthentication(HttpServletRequest request, HttpServletResponse response, FilterChain chain,
        Authentication authResult) throws IOException, ServletException {

    String secretKey = "$2y$18$1d12QDK72RFixzHcDqKYjODHA36NAsKm1RIu5V1DsgbPJAxvH0R22";
    SecretKey key = Keys.hmacShaKeyFor(secretKey.getBytes());
    long expiredDate = 900000000;

    String tokenStr = Jwts.builder().signWith(key).setSubject(authResult.getName())
            .setExpiration(new Date(new Date().getTime() + expiredDate)).compact();

    UserHelper usr = new UserHelper();
    User u = new User();
    System.out.println(authResult.getName());
    String uname = authResult.getName();
    System.out.println(uname);
    try {
        u = userService.findByUname(uname, uname);
        usr.setUser(u);
        usr.setToken(tokenStr);
    } catch (Exception e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

    response.setContentType("application/json");
    response.getWriter().append("{\"token\":\"" + tokenStr + "\"}");

}

@Override
protected void unsuccessfulAuthentication(HttpServletRequest request, HttpServletResponse response,
        AuthenticationException failed) throws IOException, ServletException {

    response.setStatus(HttpStatus.UNAUTHORIZED.value());

}

错误信息是

***************************
APPLICATION FAILED TO START
***************************
Description:
Parameter 0 of constructor in com.lawencon.security.AuthenticationFilter required a bean of type 'org.springframework.security.authentication.AuthenticationManager' that could not be found.

Action:
Consider defining a bean of type 'org.springframework.security.authentication.AuthenticationManager' in your configuration.

我尝试在构造函数之前使用@Autowired 和@Bean，但注释的位置不允许。对于这种情况，我想发送响应 jwt 和角色名称

如果我在此代码上使用 bean 注释

@Bean(name = BeanIds.AUTHENTICATION_MANAGER)
@Override
public AuthenticationFilter(AuthenticationManager authManager) {
    this.authManager = authManager;

    super.setFilterProcessesUrl("/api/login");
}

注释是不允许的位置

【问题讨论】：

AuthManager是接口类，我在AuthFilter的构造函数中调用
你需要为那个类创建一个bean..stackoverflow.com/questions/49473634/…
@ArghyaSadhu 我试过线程中的方法，但是bean注解错误不允许定位
在您尝试创建一个给出disallowed 错误的bean 的位置添加代码
我刚刚在添加 bean 注释时更新了 bean 不允许的位置错误

标签： java spring-boot oauth-2.0

【解决方案1】：

据说，你的类中应该有默认构造函数

公共 AuthenticationFilter(){ }

【讨论】：

【解决方案2】：

@Bean 注释不能用于constructor，这就是您收到disallowed 错误的原因。

您需要创建一个新类，如下所示

@Configuration
public class SecurityConfig extends WebSecurityConfigurerAdapter {

   @Bean(name = BeanIds.AUTHENTICATION_MANAGER)
   @Override
   public AuthenticationManager authenticationManagerBean() throws Exception {
       return super.authenticationManagerBean();
   }

}

【讨论】：