无法从 Python 脚本调用 CMake

Question

我正在尝试从 Python 脚本调用 CMake 命令。这是我的代码：

cmakeCmd = ["C:\Program Files\CMake\bin\cmake.exe",'-G Visual Studio 11 Win64', 'C:\Users\MyUser\Desktop\new\myProject']
retCode = subprocess.check_call(cmakeCmd, shell=True)

但我在运行脚本时得到以下输出：

The filename, directory name, or volume label syntax is incorrect.
Traceback (most recent call last):
  File "C:\Users\ochitaya\Desktop\New\myProj\sc.py", line 10, in <module>
    retCode = subprocess.check_call(cmakeCmd, stderr=subprocess.STDOUT, shell=True)
  File "C:\Python27\lib\subprocess.py", line 541, in check_call
    raise CalledProcessError(retcode, cmd)
subprocess.CalledProcessError: Command '['C:\\Program Files\\CMake\x08in\\cmake.exe', '-G Visual Studio 11 Win64', 'C:\\Users\\ochitaya\\Desktop\new\\myProj']' returned non-zero exit status 1

Answer 1

Python 字符串中的反斜杠 (\) 是转义字符。这就是字符串 "C:\Program Files\CMake\bin\cmake.exe" 被转换为 C:\\Program Files\\CMake\x08in\\cmake.exe 的原因（注意 \b 等于 \x08）。要解决此问题，请告诉 Python 您希望字符串按原样读取，或者换句话说，作为 raw 字符串，通过在字符串前面加上 r:

cmakeCmd = [r"C:\Program Files\CMake\bin\cmake.exe",'-G Visual Studio 11 Win64', r'C:\Users\MyUser\Desktop\new\myProject']

有关此主题的更多信息，请查看string literals 上的官方文档。