在 C++11 中定义元组常量向量的更简洁方法

Question

我有一个由元组组成的常量向量，其中每个元组都包含一个键、名称、数量、值。这就是我的定义-

// tuple of key, name, quantity, value
const std::vector<std::tuple<unsigned char, std::string, unsigned char, float> > myTable{
    std::tuple<unsigned char, std::string, unsigned char, float>(0, "mango", 12, 1.01f),
    std::tuple<unsigned char, std::string, unsigned char, float>(4, "apple", 101, 22.02f),
    std::tuple<unsigned char, std::string, unsigned char, float>(21, "orange", 179, 39.03f),
};

在主函数内部，我需要每个元组的索引和所有值来处理。为简单起见，我使用以下方式打印它们-

for (int index = 0; index < myTable.size(); index++) {
    auto key = std::get<0>(myTable[index]);
    auto name = std::get<1>(myTable[index]);
    auto quantity = std::get<2>(myTable[index]);
    auto value = std::get<3>(myTable[index]);
    std::cout << " index: " << index
              << " key:" << (int)key
              << " name:" << name
              << " quantity:" << (int)quantity
              << " value:" << value
              << std::endl;
}

很明显，定义向量的方式不是那么干净。 我希望有很多更清洁的东西，比如关注-

const std::vector<std::tuple<unsigned char, std::string, unsigned char, float> > myTable{
    (0, "mango", 12, 1.01f),
    (4, "apple", 101, 22.02f),
    (21, "orange", 179, 39.03f),
};

在 C++11 中是否有更简洁的方法来定义元组的常量向量？

Answer 1

你可以使用{}:

const std::vector<std::tuple<unsigned char, std::string, unsigned char, float> > myTable{
    {0, "mango", 12, 1.01f},
    {4, "apple", 101, 22.02f},
    {21, "orange", 179, 39.03f},
};