我的 do...while 逻辑和 continue 逻辑有什么问题？

Question

我是 stackoverflow 的新手，对编程也有些陌生，所以请不要介意我的代码格式不佳。我的代码有两个问题。

1. 如果玩家键入“y”或“Y”，我用来继续循环的 continue 语句不起作用。它在只有正确猜测后终止程序，这导致我：

2.我的 continue 计数器在没有停止的情况下超过 0，我只是在程序逻辑中看不到我的错误。

我看不出我的逻辑有问题。

    #include "stdafx.h"
    #include <iostream>
    #include <iomanip>
    #include <ctime>
    #include <random>

    using namespace std;

    int getNumber(); //random number prototype
    double getScore(); //gets score
    int chances = 7; //chances to guess with
    int main()
    {
    int guess = 0, 
        random;
    char retry = 'y'; //initialize retry to 'y'
    cout << "This is a random number guessing game. " << "You will be guessing between 1-100."
     << "You have 7 chances. Good luck! \n \n" << endl;


    random = getNumber(); //give the function a variable

  do
  {

    cout << random << "\n" << "\n";
    chances--;

    cout << "Enter your guess: ";
    cin >> guess;

        if (guess == random)
        {
            cout << "You have won the game! " << "Your score was: " << getScore();

            cout << "Would you like to retry? (Y or N): ";
            cin >> retry;

            if (retry == 'y' || retry == 'Y')
            {
                chances = 7;
                guess = 0;
                getNumber();
                continue; //player can retry the game
            }
            else if (chances == 0)
            {
                cout << "You have no chances left. Retry? (Y or N): ";
                    cin >> retry;
                if (retry == 'y' || retry == 'Y')
                {
                    chances = 7;
                    guess = 0;
                    getNumber();
                    continue;
                }
            }

                return 0;
        }
        else if (guess != random)
            cout << "You got it wrong. \n" << "You have: " << chances << " chances left" << endl << endl;
        else
            cout << "Incorrect Input. Please type a number." << endl << endl;
   } while (guess != random);


return 0;
}

 int getNumber()
    {
     unsigned seed = time(0); //seed the random number
     srand(seed);

     int randNum = rand() % 10 + 1; //random number in the range of 1-10
     return randNum;
    }

Answer 1

if (retry == 'y' || 'Y')

这是不正确的逻辑，这就是为什么您的代码无法按您希望的方式运行的原因。你希望它是：

if (retry == 'y' || retry == 'Y')

在您的其他 if-else 语句中也修复此逻辑错误。

Answer 2

你会想看看this

您的continue 语句跳到末尾并检查条件guess != random，其评估结果为假并退出do while。您需要做的是将guess 重置为诸如0 之类的值，以便条件评估为true。