十六进制加法 C++

Question

我需要编写一个程序来读取两个十六进制数字，将它们转换为十进制形式，并以十进制打印出两个数字的总和。据我所知，我似乎无法获得正确的值来加起来。

 #include <iostream>
#include <iomanip>

using namespace std;
void Hex_to_Dec(char &, char &);
int main()
{
    char hex1;
    char hex2;

    cout << " Please enter a hexadecimal number: " << endl;
    cin >> hex1;

    cout << " Please enter another hexadecimal value: " << endl;
    cin >> hex2;

    Hex_to_Dec(hex1, hex2);

    cout << "The decimal sum of" << hex1 << " and " << hex2 << " is " << hex1 + hex2 << endl;

    return 0;
}

void Hex_to_Dec(char & hex1, char & hex2)
{
    std::cin >> std::hex >> hex1;
    std::cout << hex1 << std::endl;

    std::cin >> std::hex >> hex2;
    std::cout << hex2 << std::endl;
}

Answer 1

试试这个：

   int main(){

    int hex1;
    int hex2;
    cout << " Please enter a hexadecimal number: ";
    cin>>hex>>hex1;
    cout << " Please enter another hexadecimal value: ";
    cin>>hex>>hex2;
    cout<<"The decimal sum of  "<<hex1<<" and  "<<hex2<<" = "<<(hex1+hex2) ;
    return 0;
}

Answer 2

如果您必须编写自己的算法来从十六进制转换为十进制，反之亦然，那么我建议您使用以下粗略模板：

#include <iostream>
#include <string>

using namespace std;

int hexToDecimal(string);
string decimalToHex(int);

int main()
{
    cout << "Enter a hex number: ";
    string hex1;
    cin >> hex1;

    cout << "Enter a hex number: ";
    string hex2;
    cin >> hex2;

    cout << "The sum of the numbers in hex is: ";
    cout << decimalToHex(hexToDecimal(hex1) + hexToDecimal(hex2));

    return 0;
}

int hexToDecimal(string hex)
{
    // Code here.
}

string decimalToHex(int decimal)
{
    // Code here.
}