如何从用户那里获取输入并将其存储在向量中？ [复制]

Question

无法从用户那里获取输入并将其存储在向量中。怎么做？ 刚开始学习编码。

#include<iostream>
#include<vector>

int main() {
int total_even = 0;
int product_odd = 1;
std::vector<int>numbers;
std::cout << "Enter 6 digits: ";
std::cin >> numbers;

for (int i = 0; i < numbers.size(); i++) {

    if (numbers[i] % 2 == 0) {

        total_even = total_even + numbers[i];
    }
    else {
        product_odd = product_odd * numbers[i];
    }
}
std::cout << "Sum of numbers is: " << total_even << "\n";
std::cout << "Product of odd numbers is: " << product_odd << "\n";
return 0;
}

Answer 1

这是在向量中获取输入的方式：

std::vector<int> numbers;
for(int i = 0; i < /*6 in your case*/; i++) {
    int temp;
    if(scanf("%d",&temp)) {
        numbers.push_back(temp);
    }
    else {
        std::cerr << "something wrong with vector" << "\n";
    }
}

---

另一种方法是使用 for-each 循环。但是，在这种情况下，您需要事先知道尺寸：

std::vector<int> numbers(size);
for(auto& elem : numbers) {
    std::cin >> elem;
}

欲了解更多信息，请查看How does c++ std::vector work?