即使在java中使用setter，输出也不正确答案

【问题标题】：Incorrect output even with setters in java即使在java中使用setter，输出也不正确
【发布时间】：2014-12-20 20:55:38
【问题描述】：

public class Employee {
private String name;
private String jobTitle;
private String department;
private float salary;

public Employee(String name, String jobTitle, String department, float salary){
name = "";
jobTitle = "";
department = "";
salary = 0;
}

public void setName(String name) {
    this.name = name;
}
public void setJobTitle(String jobTitle){
    this.jobTitle = jobTitle;
}
public void setDepartment(String department){
    this.department = department;
}
public void setSalary(float salary){
    this.salary = salary;
}
public String getName(){
    return name;
}
 public String getJobTitle(){
    return jobTitle;
}
  public String getDepartment(){
    return department;
}
   public float getSalary(){
    return salary;
}
   public double incrementSalary() {
       return ((salary/100)*2)+ salary;


}
}

我的测试课

public class EmployeeTest {
public static void main(String[] args){

Employee employee1 = new Employee("jack","management","ccl",2567);
System.out.println(employee.getSalary());



}

}

嗨，刚开始学习 java，我无法获得正确的输出，它应该超出 2567 的薪水，但我一直得到默认值 0。我已经搞砸了，但一直得到 null 和 0s 有什么想法吗？

【问题讨论】：

嗯。当您在测试类中调用new Employee() 时，该调用什么方法？那个方法有什么作用？
修复你的构造函数

标签： java class constructor output

【解决方案1】：

问题是你的构造函数什么都不做。你应该使用this.name = name

【讨论】：

【解决方案2】：

你的构造函数没有设置任何值它应该看起来像

public Employee(String name, String jobTitle, String department,
        float salary) {
    this.name = name;
    this.jobTitle = jobTitle;
    this.department = department;
    this.salary = salary;
}

【讨论】：

【解决方案3】：

改变

public Employee(String name, String jobTitle, String department, float salary){
    name = "";
    jobTitle = "";
    department = "";
    salary = 0;
}

到

public Employee(String name, String jobTitle, String department, float salary){
    this.name=name;
    this.jobTitle=jobTitle;
    this.department=department;
    this.salary=salary;
}

【讨论】：