排序和组织字典

Question

我有一本包含很多很多键/值对的字典。

键是日期，值是全球顶级域。

我想将字典输出到一个文本文件中，以便它对相似的值进行计数和 alpha 排序，但只在同一个键内

for example:
*key:     value1:count value2:count*
date1:   au:4   be:12   com:44
date2:   az:4   com:14  net:5

代码：

with open('access_logshort.txt','rU') as f:
for line in f:
    list1 = re.search(r'(?P<Date>[0-9]{2}/[a-zA-Z]{3}/[0-9]{4})(.+)(GET|POST)\s(http://|https://)([a-zA-Z.]+)(\.)(?P<tld>[a-zA-Z]+)(/).+?"\s200',line)

    if list1 != None:
        print list1.groupdict()
        one_tuple = list1.group(1,7)
        my_dict[one_tuple[0]]=one_tuple[1]

output:
print my_dict
{'09/Mar/2004': 'hu'}
{'09/Mar/2004': 'hu'}
{'09/Mar/2004': 'com'}
{'09/Mar/2004': 'ru'}
{'09/Mar/2004': 'ru'}
{'09/Mar/2004': 'com'}

T

Answer 1

这应该适合你的情况。

from collections import defaultdict
from dateutil.parser import parse
import csv
import re

data = defaultdict(lambda: defaultdict(int))

with open('access_logshort.txt','rU') as f:
    for line in f:
        list1 = re.search(r'(?P<Date>[0-9]{2}/[a-zA-Z]{3}/[0-9]{4})(.+)(GET|POST)\s(http://|https://)([a-zA-Z.]+)(\.)(?P<tld>[a-zA-Z]+)(/).+?"\s200',line)

        if list1 is not None:
            date, domain = list1.group(1,7)
            data[date.lower()][domain.lower()] += 1

with open('my_data.csv', 'wb') as ofile:
    # add delimiter='\t' to the argument list of csv.writer if you want 
    # tsv rather than csv
    writer = csv.writer(ofile)

    for key, value in sorted(data.iteritems(), key=lambda x: parse(x[0])):
        domains = sorted(value.iteritems())
        writer.writerow([key] + ['{}:{}'.format(*d) for d in domains])

输出：

10/Mar/2004,com:2,hu:2,ru:2
09/Mar/2004,com:2,hu:2,ru:2