【发布时间】:2017-11-20 13:22:49
【问题描述】:
我正在尝试存储指向成员函数模板Derived::initialize 实例的指针,如下所示(另请参阅rextester.com。对于后代,我创建了一个simpler version 的问题。):
class Base
{
public:
typedef void (Base::*setterFunction)( unsigned );
template<unsigned N>
struct SetterInterface
{
static Base::setterFunction Function;
};
protected:
template<unsigned N>
void setterImpl( unsigned )
{
}
};
template<unsigned N>
Base::setterFunction Base::SetterInterface<N>::Function = &Base::setterImpl<N>;
class Derived : public Base
{
public:
typedef void (Derived::*Initializer)();
template<typename T , void (T::*F)( unsigned ) >
void initialize()
{
}
template<typename C>
Derived( C* )
{
Initializer initializer = &Derived::initialize<C, C::template SetterInterface<0>::Function>; // NOT OK
//Initializer initializer = &Derived::initialize<C, C::template setterImpl<0> >; // OK
}
};
int main()
{
Derived derived( (Base*)0 );
}
但我在 GCC 5.4.0(和 6.4.0)上收到错误消息
Test.cpp: In instantiation of ‘Derived::Derived(C*) [with C = Base]’:
Test.cpp:45:28: required from here
Test.cpp:37:39: error: no matches converting function ‘initialize’ to type ‘Derived::Initializer {aka void (class Derived::*)()}’
Initializer initializer = &Derived::initialize<C, C::template SetterInterface<0>::Function>;
^
Test.cpp:30:7: note: candidate is: template<class T, void (T::* F1)(unsigned int)> void Derived::initialize()
void initialize()
问题似乎出在成员函数模板参数上,因为C::template setterImpl<0> 有效,而C::template SetterInterface<0>::Function(我认为它是前者的别名)无效。例如:
Base::setterFunction f1 = &Base::setterImpl<0>;
Base::setterFunction f2 = Base::template SetterInterface<0>::Function;
【问题讨论】:
-
initialize() 非类型模板参数应该是常量表达式;在你的代码中它是一个静态成员,所以它不能工作;它可以,如果您将其声明为静态 constexpr;不管怎样,你想达到什么目的?
标签: c++ templates c++98 pointer-to-member