使用杰克逊的 LocalDateTime 解析

Question

我在将 JSON 映射到具有 LocalDateTime 的 DTO 时遇到问题。

我关注了这个帖子： JSON parse error: Can not construct instance of java.time.LocalDate: no String-argument constructor/factory method to deserialize from String value

添加到 build.gradle

implementation 'com.fasterxml.jackson.datatype:jackson-datatype-jsr310:2.11.0'

这是我的 DTO 中的变量：

@Data
public class MyDto {
    private Long teamId;

    private Map<String, List<Long>> details;

    @JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "yyyy-MM-dd HH:mm:ss")
    private LocalDateTime dateOccurred;

}

并添加了这个

public class MyApplication {
    @Autowired
    private ObjectMapper objectMapper;

    public static void main(String[] args) {
        SpringApplication.run(MyApplication.class, args);
    }

    @PostConstruct
    public void setUp() {
        objectMapper.registerModule(new JavaTimeModule());
    }
}

我错过了什么吗？我收到此错误

org.springframework.messaging.converter.MessageConversionException: Could not read JSON: Cannot construct instance of `java.time.LocalDateTime` (no Creators, like default construct, exist): no String-argument constructor/factory method to deserialize from String value ('2020-06-16 11:12:46')

谢谢！

Answer 1

感谢@mohammedkhan 的指导！

在这个答案中： JSON Java 8 LocalDateTime format in Spring Boot

spring-boot中已经有设置了，不用@AutowireObjectMapper

为 Json Deserializer 添加这个注解

@JsonDeserialize(using = LocalDateTimeDeserializer.class)
@JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "yyyy-MM-dd HH:mm:ss")
private LocalDateTime dateOccurred;

谢谢！