Python 3 输入和 if 语句

Question

我在输入问题时遇到了一些问题，该问题应该允许玩家选择 5 场起跑比赛之一。我使用了以下代码。

def racechoice():
    players.race = input('After you get a chance to think, you choose to be...') #Here race is chosen
    if players.race == "dwarf" or "Dwarf": #Race starting stats
        players.race = "Dwarf"
        players.level = 1
        players.strength = 12
        players.agility = 6
        players.inteligence = 8
        players.vitality = 14
    elif players.race == "Orc" or "orc":
        players.race = "Orc"
        players.level = 1
        players.strength = 14
        players.agility = 10
        players.inteligence = 4
        players.vitality = 12
    elif players.race == "elf" or "Elf":
        players.level = 1
        players.race = "Elf"
        players.strength = 8
        players.agility = 13
        players.inteligence = 12
        players.vitality = 7
    elif players.race == "Human" or "human":
        players.level = 1
        players.race = "Human"
        players.strength = 10
        players.agility = 10
        players.inteligence = 10
        players.vitality = 10
    elif players.race == "gnome" or "Gnome":
        players.race = "Gnome"
        players.strength = 5
        players.agility = 11
        players.intelligence = 17
        players.vitality = 7

当调用显示玩家的统计数据时：

def stats():
    print(players.name)
    print(players.race)
    print("Level: "+ str(players.level) +" Strength: "+ str(players.strength) +" Agility: " + str(players.agility) +" Inteligence: "+ str(players.inteligence) +" Vitality: "+ str(players.vitality))

无论玩家选择什么，它都会以 Dwarf 状态返回。我是 Python 新手，想知道我没有正确使用 if/elif 语句吗？ ex) 在你有机会思考之后，你选择成为……兽人 欧共体 矮人 等级：1 力量：12 敏捷：6 智力：8 活力：14

Answer 1

有问题，你应该这样做：

if players.race == "dwarf" or "players.race == Dwarf":

但更好的是，将条件更改为：

elif players.race.lower() == "orc":

也建议你使用一个类来封装功能，例如：

class Player(object):
    def __init__(self, race, level, strength, agility, inteligence, vitality):
        self.race = race
        self.level = level
        self.strength = strength
        self.agility = agility
        self.inteligence = inteligence
        self.vitality = vitality

player = Player('Dwarf', 1, 12, 6, 8, 14)

那么您的 racechoice 函数将如下所示：

def racechoice():
    race = input('After you get a chance to think, you choose to be...')
    if race.lower() == 'dwarf':
        player = Player('Dwarf', 1, 12, 6, 8, 14)
    elif race.lower() == 'orc':
        player = Player('Orc', 1, 14, 10, 4, 12)
    ...
    return player

Answer 2

您不能以这种方式使用or。您所有的if/elif 声明应采用以下形式：

if players.race == "dwarf" or players.race == "Dwarf":

"Dwarf" 本身被 Python 视为True，空字符串"" 被视为False，所以你的第一个if 总是成功的。