【发布时间】:2017-08-02 21:40:29
【问题描述】:
所以这里我有一个程序,显示解决河内难题的模拟。我的程序在大多数情况下都可以正常工作,但不会在应该终止的时候终止。一旦所有的圆盘都在 C 挂钩(C C C)上,它应该终止,但我的继续到第四个圆盘,但没有给出。应该只有三个光盘。任何帮助将不胜感激!
#include <iostream>
using namespace std;
const int num = 3;
const char from_peg = 'A';
const char to_peg = 'B';
const char temp_peg = 'C';
char position[num];
void moveDiscs(int num,int disc,char source,char dest, char spare){
if (disc == 0){
position[disc]=dest;
cout<<"Moved disc "<<disc+1<<" to peg "<<dest;
cout<<" ( ";
for(int i = 0;i<num;i++){
cout<<position[i]<<" ";
}
cout<<")"<<endl;
}else{
moveDiscs(num,disc-1,source,spare,dest);
position[disc]=dest;
cout<<"Moved disc "<<disc+1<<" to peg "<<dest;
cout<<" ( ";
for(int i = 0;i<num;i++){
cout<<position[i]<<" ";
}
cout<<")"<<endl;
moveDiscs(num,disc-1,spare,dest,source);
}
}
int main() {
cout<<"Starting Position for 3 discs are (";
for(int i = 0;i<num;i++){
position[i]='A';
cout<<position[i]<<" ";
}
cout<<")"<<endl;
moveDiscs(3,3,from_peg,to_peg,temp_peg);
return 0;
}
输出:
Starting Position for 3 discs are (A A A )
Moved disc 1 to peg C ( C A A )
Moved disc 2 to peg B ( C B A )
Moved disc 1 to peg B ( B B A )
Moved disc 3 to peg C ( B B C )
Moved disc 1 to peg A ( A B C )
Moved disc 2 to peg C ( A C C )
Moved disc 1 to peg C ( C C C )
Moved disc 4 to peg B ( C C C )
Moved disc 1 to peg B ( B C C )
Moved disc 2 to peg A ( B A C )
Moved disc 1 to peg A ( A A C )
Moved disc 3 to peg B ( A A B )
Moved disc 1 to peg C ( C A B )
Moved disc 2 to peg B ( C B B )
Moved disc 1 to peg B ( B B B )
【问题讨论】:
-
position[disc]=dest;在来自main的第一次调用中使用else块中的越界索引修改position。 -
看起来 if 块正在检查磁盘 0-3,而在 else 中它最终输出 disc+1。不会“给出”答案,但看看你如何比较光盘和输出应该会让你走上正确的轨道。
-
Aren't vectors fun? -- 即时诊断问题。
标签: c++ computer-science