如何使用spring boot将数据从一个html表单传递到多个表

Question

我编写了三个类（User、UserCredential、Address），我想使用映射将数据存储到表中。我正在使用 JSON 将数据存储到表中。

当我存储数据时，数据存储在所有表中，但在用户 ID 中显示 1，在 UserCredential id 中显示 3，在地址 ID 中显示 2，而在第一个条目中，所有 id 应为 @ 987654327@.

类是

package com.spring.demo.model;

import java.util.Date;

import javax.persistence.CascadeType;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.FetchType;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.JoinColumn;
import javax.persistence.Lob;
import javax.persistence.OneToOne;
import javax.persistence.Table;
import javax.persistence.Transient;

@Entity
@Table(name="user")
public class User {

    @Id
    @Column(name="user_id")
    @GeneratedValue(strategy=GenerationType.AUTO)
    private int id;

    private String fName;

    private String lName;

    @Column(unique=true,nullable=true)
    private String email;

    @Column(unique=true,nullable=true)
    private long mobile;

    private Date dob;

    @Lob
    private byte[] image;   

    @Transient
    private String base64Image;

    @OneToOne(cascade=CascadeType.ALL,fetch =FetchType.EAGER)
    @JoinColumn(name="userCredential_id")
    private UserCredential userCredential;

    @OneToOne(cascade=CascadeType.ALL,fetch =FetchType.EAGER)
    @JoinColumn(name="add_id")
    private Address address;



    public Address getAddress() {
        return address;
    }

    public void setAddress(Address address) {
        this.address = address;
    }

    public int getId() {
        return id;
    }

    public void setId(int id) {
        this.id = id;
    }

    public String getfName() {
        return fName;
    }

    public void setfName(String fName) {
        this.fName = fName;
    }

    public String getlName() {
        return lName;
    }

    public void setlName(String lName) {
        this.lName = lName;
    }

    public String getEmail() {
        return email;
    }

    public void setEmail(String email) {
        this.email = email;
    }

    public long getMobile() {
        return mobile;
    }

    public void setMobile(long mobile) {
        this.mobile = mobile;
    }

    public Date getDob() {
        return dob;
    }

    public void setDob(Date dob) {
        this.dob = dob;
    }

    public byte[] getImage() {
        return image;
    }

    public void setImage(byte[] image) {
        this.image = image;
    }

    public UserCredential getUserCredential() {
        return userCredential;
    }

    public void setUserCredential(UserCredential userCredential) {
        this.userCreenter code heredential = userCredential;
    }



}

UserCredential.java

package com.spring.demo.model;

import javax.persistence.CascadeType;
import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.FetchType;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.JoinColumn;
import javax.persistence.OneToOne;

import com.fasterxml.jackson.annotation.JsonIgnore;

     @Entity
public class UserCredential {

    @Id
    @Column(name="credential_id")
    @GeneratedValue(strategy=GenerationType.AUTO)
    private int id;

    @Column(unique=true,nullable=true)
    private String username;

    private String password;
    private String cnfrmpassword;



    @JsonIgnore
    @OneToOne(cascade=CascadeType.ALL)
    @JoinColumn(name="user_id")
    private User user;

    public int getId() {
        return id;
    }
    public void setId(int id) {
        this.id = id;
    }
    public String getUsername() {
        return username;
    }
    public void setUsername(String username) {
        this.username = username;
    }
    public String getPassword() {
        return password;
    }
    public void setPassword(String password) {
        this.password = password;
    }
    public String getCnfrmpassword() {
        return cnfrmpassword;
    }
    public void setCnfrmpassword(String cnfrmpassword) {
        this.cnfrmpassword = cnfrmpassword;
    }

    public User getUser() {
        return user;
    }
    public void setUser(User user) {
        this.user = user;
    }

}

Address.java

package com.spring.demo.model;

import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.JoinColumn;
import javax.persistence.ManyToOne;
import javax.persistence.Table;

@Entity
@Table(name="address")
public class Address {

    @Id
    @GeneratedValue(strategy=GenerationType.AUTO)
    @Column(name="add_id")
    private int id;

    @Column(name="city")
    private String city;

    @Column(name="state")
    private String state;

    @Column(name="house_no")
    private String h_no;

    @ManyToOne
    @JoinColumn(name="user_id", nullable=true)
    private User user;

    public int getId() {
        return id;
    }

    public void setId(int id) {
        this.id = id;
    }

    public String getCity() {
        return city;
    }

    public void setCity(String city) {
        this.city = city;
    }

    public String getState() {
        return state;
    }

    public void setState(String state) {
        this.state = state;
    }

    public String getH_no() {
        return h_no;
    }

    public void setH_no(String h_no) {
        this.h_no = h_no;
    }

    public User getUser() {
        return user;
    }

    public void setUser(User user) {
        this.user = user;
    }

}

我真的不明白如何克服这个问题。

JSON格式存储数据

{

    "fName":"suresh kumst",
    "lName":"dingh",
    "mobile":4595498366,
    "email":"ksuraj1sd00@gmail.com",
    "dob":"2012-04-23T18:25:43.511Z",
    "address":{
        "city":"noida",
        "state":"up",
        "h_no":"123"
    },
    "userCredential":{

        "username":"ksuraj1asd002",
        "password":"12345",
        "cnfrmpassword":"12345"
    }
}

和不同id的响应，虽然它们在第一个条目中应该是1并且用户id应该有值

    {
        "id": 1,
        "fName": "suresh kumst",
        "lName": "dingh",
        "email": "ksuraj1sd00@gmail.com",
        "mobile": 4595498366,
        "dob": "2012-04-23T18:25:43.511+0000",
        "image": null,
        "userCredential": {
            "id": 3,
            "username": "ksuraj1asd002",
            "password": "12345",
            "cnfrmpassword": "12345"
        },
        "address": {
            "id": 2,
            "city": "noida",
            "state": "up",
            "h_no": "123",
            "user": null
        }
    }

Answer 1

在这里，您使用的是@GeneratedValue(strategy=GenerationType.AUTO)。 一些数据库将使用一个通用序列来生成和分配序列号。 Hibernate会创建一个表hibernate_sequence，所有的实体表都会引用这个表来获取下一个序列号。因此，主键将分散在实体之间。 要使每个实体的主键从 1 开始，请对每个实体使用 @GeneratedValue(strategy=GenerationType.IDENTITY)。

Answer 2

当您使用@GeneratedValue(strategy=GenerationType.AUTO) 时，底层 ORM 框架将使用标识列、序列或表，具体取决于底层数据库。在您的情况下，我猜它正在使用一个序列（用于为所有表生成 ID 的单个序列）。如果是这种情况，为了实现每个表 ID 独立于其他表，您必须为每个实体赋予不同的序列名称。

如果您使用的是 Hibernate，请考虑使用 @GenericGenerator。来自其他SO answer的示例：

@GenericGenerator(
    name = "wikiSequenceGenerator",
    strategy = "org.hibernate.id.enhanced.SequenceStyleGenerator",
    parameters = {
            @Parameter(name = "sequence_name", value = "WIKI_SEQUENCE"),
            @Parameter(name = "initial_value", value = "1000"),
            @Parameter(name = "increment_size", value = "1")
    }
)
@Id
@GeneratedValue(generator = "wikiSequenceGenerator")

Answer 3

请使用 DB 序列，以便更好地控制生成的 ID，这里我只是分享一个假设后端 DB 为 Oracle/mysql

的示例

 @Id
   @GeneratedValue(strategy=GenerationType.AUTO, generator = "employee_sequence")
   @SequenceGenerator(name = "employee_sequence", sequenceName = "EMP_SN")
    private Long empNo;

这里EMP_SN 是数据库序列。 希望这能解决您的问题。