【发布时间】:2015-10-28 09:18:41
【问题描述】:
我一直在做一个简单的电子邮件验证。但它不起作用。
任何想法为什么它不起作用?我做错了什么还是应该以其他方式构建我的代码?
我做了一个这样的功能:
function IsEmail(email) {
var regex = /^([a-zA-Z0-9_\.\-\+])+\@(([a-zA-Z0-9\-])+\.)+([a-zA-Z0-9]{2,4})+$/;
if(!regex.test(email)) {
return false;
} else {
return true;
}
}
然后我在 setupRegistration 函数中调用该函数。
我的 JS 看起来像这样:
function doOutputMessage(type, message){
$("#outputMessage").html("");
$("#outputMessage").removeClass();
$("#outputMessage").hide();
if(type == "error") {
$("#outputMessage").addClass("error").fadeIn("fast");
} else if(type == "success") {
$("#outputMessage").addClass("success").fadeIn("fast");
}
$("#outputMessage").text(message);
$("#outputMessage").show();
}
function setupRegistration(){
$("#signupWrapper").on("click", "#regUser", function(){
var username = $("input[name='username']").val();
var email = $("input[type='email']").val();
var password = $("input[type='password']").val();
if(username == ""){
doOutputMessage("error", "Fill in your desired username!");
}
if(email == ""){
doOutputMessage("error", "Fill in your email!");
}
if(IsEmail(email)==false){
doOutputMessage("error", "mailen är fel förfan");
}
if(password == ""){
doOutputMessage("error", "Fill in your desired password!");
}
if(username != "" && email != "" && password != ""){
ajaxCall(username, email, password);
}
});
}
function IsEmail(email) {
var regex = /^([a-zA-Z0-9_\.\-\+])+\@(([a-zA-Z0-9\-])+\.)+([a-zA-Z0-9]{2,4})+$/;
if(!regex.test(email)) {
return false;
}else{
return true;
}
}
function ajaxCall(username, email, password){
$.ajax({
type: 'POST',
url: '../register.php',
data: {
'username' : username,
'email' : email,
'password' : password,
},
success: function(data) {
if(data.exists){
doOutputMessage("error","That Username is allready taken.");
} else if(data.inserted) {
doOutputMessage("success","You have successfully been registered!");
}else {
doOutputMessage("error","Something went wrong, try again later.");
}
}
});
}
$(document).ready(function(){
setupRegistration();
});
function regSubmit(){
clearErrorMessages();
var username = $("#regForm #username").val();
var email = $("#regForm #email").val();
var password = $("#regForm #password").val();
if(username == ""){
showValidationMessage("#regForm #error_username", "Fill in your desired username!");
}
if(email == ""){
showValidationMessage("#regForm #error_email", "Fill in your email!");
}
if(password == ""){
showValidationMessage("#regForm #error_password", "Fill in your desired password!");
}
if(username != "" && email != "" && password != ""){
$.ajax({
url: 'regLogin.code.php',
type: 'POST',
data: {
'action' : 'register',
'username' : username,
'email' : email,
'password' : password
},
success: function(data, status){
console.log(data);
if(data == "exist"){
showValidationMessage("#regForm #error_general", "A user with that username or password already exists!");
}else if(data == "illegal"){
showValidationMessage("#regForm #error_general", "Your username contains illegal characters!");
}
else if(data == "true"){
showValidationMessage("#regForm #success", "Success!");
setTimeout(function(){
window.location.replace("/admin/inside/");
}, 1000);
}
},
error: function(xhr, desc, err){
showValidationMessage("#regForm #error_general", "Something went wrong, please try again");
}
});
}
}
【问题讨论】:
-
试试用
if(!IsEmail(email)){代替if(IsEmail(email)==false){ -
应该正则表达式类似于:/^([\w-\.]+@([\w-]+\.)+[\w-]{2,4})? $/
-
其他表单验证是否有效?
-
@DavidSkx 是的,其他一切正常。你可以在这里查看:regform.jonasalvarson.se
-
即使 isEmail 为 false,它也会显示错误,但不会停止 Ajax 调用: if(username != "" && email != "" && password != "" ){ ajaxCall(用户名、邮箱、密码); }
标签: javascript jquery validation email