【发布时间】:2016-01-22 19:17:56
【问题描述】:
这是我的代码。问题是当我单击模式上的确认按钮时表单正在提交。问题是我不知道如何在提交之前先验证表单。这就是我想要的过程。
1. 用户填写字段。
2. 用户单击确认按钮(至少此处必须验证表单)或此处
3. 模态显示,当我单击提交按钮时,模态将关闭,然后将显示表单验证
<form role="form" id="formfield" action="<?php echo base_url()?>Shop/add_shop" method="post" enctype="multipart/form-data">
<div class="row">
<div class="col-md-10 col-md-offset-1">
<p><B>Shop name:</b></p>
<input type="text" class="form-control" id ="shop_name" name="shop_name">
</div>
<div class="col-md-1"></div>
</div>
<div class="modal fade" id="confirm-submit" tabindex="-1" role="dialog" aria-labelledby="myModalLabel" aria-hidden="true">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-header">
Confirm Submit
</div>
<form action="<?php echo base_url()?>Shop/add_shop" id="wew" method="post">
<div class="modal-body">
Are you sure you want to submit the following details?
<table class="table">
<tr>
<th>Shop Name: </th>
<td ><input type="text " id="s_name" name="shop_name" readonly></td>
</tr>
</table>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-default" data-dismiss="modal">Cancel</button>
<button href="#" onclick="document.getElementById('formfield').submit();" class="btn btn-success success">Submit</button>
</div>
</form>
</div>
</div>
</div>
<script type="text/javascript">
$('#submitBtn').click(function() {
$('#s_name').val($('#shop_name').val());
});
$('#submit').click(function(){
$('#formfield').submit();
});
</script>
【问题讨论】:
标签: javascript php jquery html validation