【发布时间】:2011-02-18 14:37:05
【问题描述】:
我有一个相当复杂的搜索,它利用了多个 ajax 调用,流程如下:
user performs search on button click
ajax request is made to php page which returns json data
for each result in returned data additional ajax request is made
run function which makes additional ajax call
end for each
end click function
这一切都很好,我想做的是在 div 中显示加载消息并禁用搜索按钮,然后当所有 ajax 请求完成后重新启用按钮并删除加载消息。
我的脚本在下面,此时按钮的禁用/重新启用几乎是瞬间发生的,我认为因为 ajax 调用是异步的,一旦所有 ajax 请求,我该如何重新启用按钮并删除加载消息完成并显示数据了吗??
$('#advKeyBtn').live('click', function() {
$('#advKeyBtn').attr('disabled', 'disabled');
$('#searchStatus').html('<img src="../img/icons/loadinfo.gif" width="16" height="16" /> Searching Locations...');
$('#results').html(''); //clear existing contents
$('#borough_links').html(''); //clear existing contents
// handler for advance search button
var myUrl = 'getKeyBoroughs.php';
var myKeys = $('#keywords').val();
var myType = $('input[name=keyParams]:checked').val()
$.ajax({
url: myUrl,
data: "keys=" + myKeys +'&type='+myType,
type: "POST",
traditional: false,
dataType: 'json',
error: function(xhr, statusText, errorThrown){
// Work out what the error was and display the appropriate message
},
success: function(myData){
// data retrived ok
$.each(myData.boroughs, function( intIndex, objValue ){
//alert(myData.boroughs[intIndex].Borough_ID);
makeCSS(myData.boroughs[intIndex].Borough_ID);
getKeyLocations(myData.boroughs[intIndex].Borough_ID)
})
//$('#'+divId).append(myData)//construct location holders
}
});
$('#advKeyBtn').attr('disabled', '');
$('#searchStatus').html('Search Complete, click on an area to view locations');
});
以及从主 ajax 调用的初始成功中调用的函数
function getKeyLocations(id){
var myUrl = 'getKeyLocations.php';
var myBorough = id;
var myKeys = $('#keywords').val();
var myType = $('input[name=keyParams]:checked').val()
var divId = '#borough_'+ id;
$.ajax({
url: myUrl,
type: 'POST',
data: 'borough_id='+myBorough+'&keys='+myKeys,
error: function(xhr, statusText, errorThrown){
// Work out what the error was and display the appropriate message
},
success: function(myData){
$(divId).html(myData);
}
});
};
【问题讨论】:
-
看起来您的客户端 javascript 执行通常由服务器处理的控制器级功能。这是你安排事情的唯一方法吗?