将数据从 jstree 插入数据库

Question

我很难弄清楚如何接收一组 id 或完整的节点信息并使用该数据将对应的行插入到数据库中。

为什么会这样？好吧，我有以下层次结构 projeto>uc>ambiente>secao>med。在我的 JS 树中，我正在使用延迟加载，所以假设用户选择了一个“projeto”，他们提交的只是我得到的“projeto”id，所以这很容易，我知道我必须在 db 上插入它的所有子项和他们的孩子。但是假设用户选择了一个特定的“ambiente”或一个特定的“secao”，我得到的只是一个 id 或一个节点数据，但是要插入该信息，我需要先插入它的所有父数据，然后才能将其插入分贝。

示例 1 单个“项目”选定数据。

[{"id":"projeto_1","text":"Pr\u00e9dios P\u00fablicos","icon":"fa fa-folder icon-lg icon-state-info","parent":"#","parents":["#"],"data":{"id_mobile":"1"},"state":{"loaded":"false","opened":"false","selected":"true","disabled":"false"},"li_attr":{"id":"projeto_1"},"a_attr":{"href":"#"},"original":{"id":"projeto_1","text":"Pr\u00e9dios P\u00fablicos","icon":"fa fa-folder icon-lg icon-state-info"}}]

示例 2 选择了单个“ambiente”，可能有或没有“secao”子级。

[{"id":"ambiente_4","text":"protocolo","icon":"fa fa-folder icon-lg icon-state-info","parent":"uc_1","parents":["uc_1","projeto_1","#"],"data":{"id_ambiente_mobile":"4"},"state":{"loaded":"false","opened":"false","selected":"true","disabled":"false"},"li_attr":{"id":"ambiente_4"},"a_attr":{"href":"#"},"original":{"id":"ambiente_4","text":"protocolo","icon":"fa fa-folder icon-lg icon-state-info","type":"ambiente"}}]

示例 3 单个 'secao' 选定数据。

[{"id":"secao_5","text":"1 Lumin\u00e1ria(s) LFT 1X40W","icon":"fa fa-folder icon-lg icon-state-info","parent":"ambiente_5","parents":["ambiente_5","uc_1","projeto_1","#"],"data":{"id_secao_mobile":"5"},"state":{"loaded":"false","opened":"false","selected":"true","disabled":"false"},"li_attr":{"id":"secao_5"},"a_attr":{"href":"#"},"original":{"id":"secao_5","text":"1 Lumin\u00e1ria(s) LFT 1X40W","icon":"fa fa-folder icon-lg icon-state-info","type":"secao"}},{"id":"ambiente_5","text":"Recep\u00e7\u00e3o","icon":"fa fa-folder icon-lg icon-state-info","parent":"uc_1","parents":["uc_1","projeto_1","#"],"children":["secao_5"],"children_d":["secao_5"],"data":{"id_ambiente_mobile":"5"},"state":{"loaded":"true","opened":"true","selected":"true","disabled":"false","loading":"false"},"li_attr":{"id":"ambiente_5"},"a_attr":{"href":"#"},"original":{"id":"ambiente_5","text":"Recep\u00e7\u00e3o","icon":"fa fa-folder icon-lg icon-state-info","type":"ambiente"}}]

上面所有的数据都是传给php文件的数据。所以我只是 jso_encoded 并在这里发布。

所以我需要将选定的节点插入数据库，但考虑到如果父节点未加载到树上，它可能有子节点。当然，当我选择一个孩子并需要迭代所有备份时，他们会在插入孩子之前将其插入父依赖项（最后两个示例）。

希望你们能帮助我。如果需要任何澄清，请询问。

谢谢。

Answer 1

好的，伙计们已经完成了一半。创建了以下代码：

//take the actual node.
for ($i = 0; $i < count($ids); $i++) {

    //if the actual node is loaded and opened.
    if (($ids[$i]['state']['loaded'] == true) && ($ids[$i]['state']['opened'] == true)) {
        //then the node is inserted in the db.
        checaNo ($ids[$i]);
        //and the iteration jump all it's selected children. This is because checaNo already insert all actual node children.
        $i = count($ids[$i]['children'])+1;

    }
    //the actual node has not any children or it's children is not loaded.
    else
    {
        //insert the node and it's children if they exists. Then go to the next node.
        checaNo($ids[$i]);
    }

}

现在的问题是，假设我已经选择了一个“ambiente”作为新的“projeto”，所以在我插入创建它的父母所需的“ambiente”数据之前。在这个例子中是“projeto”和“uc”，需要插入“projeto”，然后需要插入“uc”，然后我才能在db上插入“ambiente”。

编辑：好的，这就是我为解决这个问题所做的。创建了以下函数

function checaPai ($no) {

    global $data;

    $nivel = count($no['parents'])-1;

    switch ($nivel) {
        case 0;
            break;
        case 1;
            $args_projeto = new stdClass();
            $id_projeto = explode("_", $no['parent']);
            $args_projeto->where = "data_hora_importacao = '$data' AND id_mobile = '" . $id_projeto[1]."'";

            $projeto = getMobileProjeto($args_projeto);

            $args_projeto_online = new stdClass();
            $args_projeto_online->where = "id = '" . $projeto[0]->id_online."'";
            $projeto_online = getOnlineProjeto($args_projeto_online);

            if (count($projeto_online) == 0) {

                $id_projeto = insereProjeto($args_projeto, false);

                return $id_projeto;
            }
            else {

                return $projeto_online[0]->id;

            }

            break;
        case 2;
            $args_uc = new stdClass();
            $id_uc = explode("_", $no['parent']);
            $args_uc->where = "data_hora_importacao = '$data' AND id_uc_mobile = '" . $id_uc[1]."'";
            $uc = getMobileUC($args_uc);

            $args_uc_online = new stdClass();
            $args_uc_online->where = "contrato = '" . $uc[0]->contrato."'";
            $uc_online = getOnlineUC($args_uc_online);

            if (count($uc_online) == 0) {


                $no_uc = array();
                $no_uc['parent'] = $uc->projeto;
                $id_uc = checaPai($no_uc);
                return $id_uc;
            }
            else {

                return $uc_online[0]->id;
            }

            break;
        case 3;
            break;
        case 4;
            break;
    }
}

上面的函数检查它的父级是否存在，然后插入或创建它所有的子级。例如，当孩子有 2 或 3 个级别时，函数会调用自身并返回父 ID。而已。

这是不完整且丑陋的，但为了澄清起见，也许如果有人遇到同样的问题，他们可以看到我的想法。