获取具有多个选择值 Codeigniter 的选定选择选项表单数据库

Question

这是我的表，你可以从我下面的表中看到，在 1 column 我们可以输入 2 values，我的问题是如何获取该值并将其放入正确的 select option

 No  |  Course_Code  | Course_Score |
  1  |  CC001,CC002  |     A, B     |
  2  |  CC003,       |     C,       | 

这是我的选择选项，你可以看到我有 4 个不同的选择，或者你称之为下拉菜单，当我点击 edit 按钮时，我想将第一个 course_code 放入正确的 @987654328 @select 并将course_score 放入正确的课程分数中，我该怎么做？

这就是我如何在我的表中放入 2 个值以及我的函数以获取 Course

public function save(id=null){
    'Course_code'=>$this->input->post("course_code1").', '.$this->input->post("course_code2"),
    'Course_Score'=>$this->input->post("course_score1").', '.$this->input->post("course_score2")
}
public function combo_course(){
    //GET ALL COURSE LIST
    $kodePro = $this->input->post('pro_id');//09
    $matkulCombo = $this->cms_matakuliah_m->getMatkul($this->session->userdata('kodePS'))->result();
    $list_combo = "";
    $list_combo .= "<option value='0'>Choose</option>";
    foreach($matkulCombo as $rows):
        $list_combo .="<option value='".$rows->Course_code."'>".$rows->Course_name."</option>";
    endforeach;
    echo $list_combo;
}

这是我的看法

<select  id="courseCode" class="form-control">
//I use AJAX to get the Course
</select>
<select disabled id="cScore" class="form-control">
   <option value="">Choose</option>
   <option value="A" <?php if(isset($matkul->Course_Score)) echo ($matkul->Course_Score == 1)?"selected":"" ?>>A</option>
   <option value="B" <?php if(isset($matkul->Course_Score)) echo ($matkul->Course_Score == 2)?"selected":"" ?>>B</option>
   <option value="C" <?php if(isset($matkul->Course_Score)) echo ($matkul->Course_Score == 3)?"selected":"" ?>>C</option>
   <option value="D" <?php if(isset($matkul->Course_Score)) echo ($matkul->Course_Score == 4)?"selected":"" ?>>D</option>
   <option value="E" <?php if(isset($matkul->Course_Score)) echo ($matkul->Course_Score == 5)?"selected":"" ?>>E</option>

Answer 1

使用表单助手然后传递默认值

echo form_dropdown('course_code1', $get_matkul, $currentValue, "id='courseCode' class='input-large'");

• 第一个参数是元素的名称
• 第二个是选项
• 第三个是选定的值
• 第四个是属性

Answer 2

<?php 
//    $get_matkul is course codes from database table. right?
$get_scores = mysqli_fetch_array($result);//(a,b,c,d,...) from table
$Course_codes = explode(',',$matkul->Course_code);
$Course_Scores = explode(',',$matkul->Course_Score);?>
<select  id="courseCode" class="form-control">
    <option value="">Choose</option>
    <?php foreach($get_matkul as $rows): 
        $selected = "";
        foreach($Course_codes as $Course_code){
            if($Course_code == $rows->Course_code){
                $selected = "Selected";
            }
        }?>
    <option value="<?php echo $rows->Course_code?>" <?php echo $selected;?> >
        <?php echo $rows->Course_name ?>
    </option>
    <?php endforeach; ?>
</select>
<select disabled id="cScore" class="form-control">
    <option value="">Choose</option>
    <?php foreach($get_scores as $score): 
        $selected = "";
        foreach($Course_Scores as $Course_Score){
            if($Course_Score == $score->Course_Score){
                $selected = "Selected";
            }
        }?>
    <option value="<?php echo $score->Course_Score;?>" <?php echo $selected ?>><?php echo $score->Course_Score;?></option>
    <?php endforeach; ?>
</select>