【发布时间】:2015-11-26 22:37:09
【问题描述】:
我搜索this question 中突出显示的问题的解决方案。
不幸的是,已接受的解决方案(可追溯到 2012 年 11 月 21 日)不再有效,您可以在 this demo 中这样做。
有人知道为什么吗?
身体
<div id="fb-root"></div>
<script src="http://connect.facebook.net/en_US/all.js"></script>
<script>
FB.init({
appId : '179378788777832',
status : true,
cookie : true,
xfbml : true
});
</script>
<div id="login">
You are not logged in to FB, Please click<a href="#"> here </a> to login.
</div>
<div id="container_notlike">
YOU DONT LIKE
</div>
<div id="container_like">
YOU LIKE
</div>
JS
var hideLogin = function(){
$("#login").hide();
}
var showLogin = function(){
$("#login").show();
}
var doLogin = function(){
FB.login(function(response) {
if (response.session) {
hideLogin();
checkLike(response.session.uid)
} else {
// user is not logged in
}
});
}
var checkLike = function(user_id){
var page_id = "40796308305"; //coca cola
var fql_query = "SELECT uid FROM page_fan WHERE page_id = "+page_id+"and uid="+user_id;
var the_query = FB.Data.query(fql_query);
the_query.wait(function(rows) {
if (rows.length == 1 && rows[0].uid == user_id) {
$("#container_like").show();
//here you could also do some ajax and get the content for a "liker" instead of simply showing a hidden div in the page.
} else {
$("#container_notlike").show();
//and here you could get the content for a non liker in ajax...
}
});
}
$(document).ready(function(){
FB.getLoginStatus(function(response) {
if (response.status === 'connected') {
hideLogin();
checkLike(response.authResponse.userID)
} else {
showLogin();
}
});
$("#login a").click(doLogin);
});
CSS
body {
width:520px;
margin:0; padding:0; border:0;
font-family: verdana;
background:url(repeat.png) repeat;
margin-bottom:10px;
}
p, h1 {width:450px; margin-left:50px; color:#FFF;}
p {font-size:11px;}
#container_notlike, #container_like, #login {
display:none
}
我搜索了几个小时的解决方案,但没有找到任何可行的方法。
感谢您的帮助。
【问题讨论】:
标签: facebook web facebook-javascript-sdk facebook-like