如何（SUM）在数据透视表字段中并在 yajra-laravel-datatable 包中搜索该字段（laravel 5.6）

Question

！三张桌子

1. 库存 enter image description here
2. 仓库 enter image description here
3. inventory_has_warehouses enter image description here

我用过laravel yajra datatable。我需要在 inventory_has_warehouses 数据透视表中对 starting_balance 这个字段进行求和和搜索

我的代码：

    $id = Auth::user()->id;

        $row = Inventory::with('contact')->with('warehouse')
        ->select(
          'inventories.*',
          DB::raw('SUM(inventory_has_warehouses.starting_balance) as total') 
        )
        ->leftJoin('inventory_has_warehouses', 'inventory_has_warehouses.inventory_id', '=', 'inventories.id')
        ->leftJoin('warehouses', 'warehouses.id', '=', 'inventory_has_warehouses.warehouse_id')
        ->where('inventories.subscriber_id',$id)
        ->groupBy('inventories.id');

        $datatable = DataTables::of($row)

        ->filterColumn('total', function($query, $keyword) {
            $query->whereRaw('sum(inventory_has_warehouses.starting_balance) like ?', ['%'.$keyword.'%']);

        })

        return $datatable->make(true);

但我发现这种类型的错误

异常消息：↵↵SQLSTATE[HY000]：一般错误：1111 无效使用 组函数 (SQL: select count() as aggregate from (select inventories.，SUM(inventory_has_warehouses.starting_balance) 为 总计从inventories 左加入inventory_has_warehouses on inventory_has_warehouses.inventory_id = inventories.id 左 加入warehouseswarehouses.id = inventory_has_warehouses.warehouse_id 在哪里 inventories.subscriber_id = 2 和 inventories.status = 1 和 (LOWER(inventories.itemcode) 喜欢 %1% 或 LOWER(inventories.purchasedescription) LIKE %1% 或存在（选择 * 来自contacts 其中inventories.supplier = contacts.id 和 LOWER(contacts.name) LIKE %1%) 或 (sum(inventory_has_warehouses.starting_balance) like %1%)) 分组 inventories.id) count_row_table)

mysql查询

选择库存。SUM(inventory_has_warehouses.starting_balance) 作为剩余库存的总数，加入inventory_has_warehouses on inventory_has_warehouses.inventory_id = inventory.id 离开加入 仓库上的仓库.id = inventory_has_warehouses.warehouse_id 其中 inventory.subscriber_id = 2 和 inventory.status = 1 和 (LOWER(inventories.itemcode) LIKE %1% 或 LOWER(inventories.purchasedescription) LIKE %1% 或存在（选择 * 来自inventories.supplier = contacts.id的联系人和 LOWER(contacts.name) LIKE %1%) 或 (sum(inventory_has_warehouses.starting_balance) like %1%)) 分组 库存.id

Answer 1

$id = Auth::user()->id;
        $row = DB::table('inventories')->select('inventories.*','contacts.name',DB::raw('SUM(inventory_has_warehouses.starting_balance) as total'))
            ->leftJoin('contacts', 'inventories.supplier', '=', 'contacts.id')
            ->leftJoin('inventory_has_warehouses', 'inventories.id', '=', 'inventory_has_warehouses.inventory_id')
            ->where('inventories.subscriber_id',$id)
            ->groupBy('inventory_has_warehouses.inventory_id');

if ($keyword = $request->get('search')['value']) {
            $row->having(DB::raw('SUM(inventory_has_warehouses.starting_balance)'), 'like', '%'.$keyword.'%');
            $row->orHaving('inventories.itemcode', 'like', '%'.$keyword.'%');
            $row->orHaving('inventories.purchasedescription', 'like', '%'.$keyword.'%');
            $row->orHaving('contacts.name', 'like', '%'.$keyword.'%');
          }

$datatable = DataTables::of($row)

->filterColumn('total', function($query, $keyword) {
        })

return $datatable->make(true);

Answer 2

尝试按 inventory_has_warehouses.inventory_id 分组

编辑答案：

你真的很难让别人阅读你的查询并给你帮助，但在这里更正你的查询是一个重新格式化的更正查询：

SELECT 
inventories.*, 
SUM(inventory_has_warehouses.starting_balance) as total 
FROM
inventories LEFT JOIN inventory_has_warehouses 
ON 
inventory_has_warehouses.inventory_id = inventories.id LEFT JOIN warehouses 
ON
warehouses.id = inventory_has_warehouses.warehouse_id 
WHERE
inventories.subscriber_id = 2 
AND
inventories.status = 1 
AND
(LOWER(inventories.itemcode) LIKE '%1%' or LOWER(inventories.purchasedescription) 
LIKE '%1%' OR EXISTS 
(SELECT 
* 
FROM
contacts 
WHERE
inventories.supplier = contacts.id 
AND
LOWER(contacts.name) LIKE '%1%') 
OR
(SUM(inventory_has_warehouses.starting_balance) LIKE '%1%')) GROUP BY inventories.id

您发送的查询的问题是您的like 语句只有这个：

LIKE %1%

这个语句需要字符串，它只说：

inventories.

这应该特定于您需要的列，或者只使用库存。* 来显示该表的所有列，但错误仍然没有意义，因为它说和：

select count() as aggregate

也许其中一个可以解决，但是在重新格式化您的代码时，我首先注意到语法错误，但这是非常基本的，也许您现在可以开始运行一个非常简单的查询，这可能是适合您的查询：

SELECT 
    inventories.id AS inventory_id,
    warehouses.id,
    SUM(inventory_has_warehouses.starting_balance) AS total
    FROM
    inventories LEFT JOIN inventory_has_warehouses
    ON inventories.id = inventory_has_warehouses.inventory_id
    LEFT JOIN
    warehouses 
    ON warehouses.id = inventory_has_warehouses.warehouse_id
    GROUP BY
    inventory_has_warehouses.inventory_id

从这里开始一一添加条件，直到再次出现错误（在mysql查询窗口上执行此操作，而不是通过laravel代码）尚不确定laravel如何处理sql查询，但您发送的格式确实会导致错误，如果您要在此处发布问题，请确保使其易于阅读，否则有人可能会抨击您，导致难以阅读格式不正确的代码。 ;)

还有一件事我忘了确保inventories.id 是该表的主键，否则这仍然会导致您出错，请参阅此链接了解更多详细信息https://dev.mysql.com/doc/refman/5.7/en/group-by-handling.html