AngularJS数组迭代对象并比较其中的字符串答案

【问题标题】：AngularJS array iterate object and compare strings inside itAngularJS数组迭代对象并比较其中的字符串
【发布时间】：2021-02-22 14:11:47
【问题描述】：

我正在开发一个 AngularJS 项目，该项目旨在在前端显示我们在线商店的名称、位置和营业时间。

前端的示例预期结果：

JSON 数据结构如下所示：

[
  {
    "address": {
      "city": "Haarlem",
      "housenumber": "89",
      "streetname": "Zilweg-Oost",
      "zipcode": "2013 EG"
    },
    "pickupName": "Haarlem Pick-up Point 89",
    "operatingHours": {
      "Friday": {
        "string": "09:00-19:00"
      },
      "Monday": {
        "string": "09:00-19:00"
      },
      "Saturday": {
        "string": "10:00-21:00"
      },
      "Thursday": {
        "string": "09:00-19:00"
      },
      "Tuesday": {
        "string": "09:00-19:00"
      },
      "Wednesday": {
        "string": "09:00-19:00"
      }
    }
  },
  {
    "address": {
      "city": "Haarlem",
      "housenumber": "19",
      "streetname": "Zilweg-Oost",
      "zipcode": "2013 AF"
    },
    "pickupName": "Gamma Ray Den Haarlem",
    "operatingHours": {
      "Friday": {
        "string": "09:00-19:00"
      },
      "Monday": {
        "string": "09:00-19:00"
      },
      "Saturday": {
        "string": "09:00-19:00"
      },
      "Sunday": {
        "string": "13:00-17:00"
      },
      "Thursday": {
        "string": "09:00-19:00"
      },
      "Tuesday": {
        "string": "09:00-19:00"
      },
      "Wednesday": {
        "string": "09:00-19:00"
      }
    }
  },
  {
    "address": {
      "city": "Haarlem",
      "housenumber": "183",
      "streetname": "Zilweg",
      "zipcode": "2015 BG"
    },
    "pickupName": "Uitvaartcentrum Omega Point",
    "operatingHours": {
      "Friday": {
        "string": "09:00-19:00"
      },
      "Saturday": {
        "string": "10:00-17:00"
      },
       "Saturday": {
        "string": "12:00-17:00"
      },
      "Thursday": {
        "string": "09:00-19:00"
      },
      "Tuesday": {
        "string": "09:00-19:00"
      },
      "Wednesday": {
        "string": "09:00-19:00"
      }
    }
  },
]

我尝试获取 operatingHours 对象并将其推送到单独的数组中。

现在我的问题是如何迭代、比较每个字符串并验证周一时间是否与周六时间相同等，然后将其显示在我的页面上？

【问题讨论】：

标签： arrays angularjs

【解决方案1】：

如果您只想比较不同日期的时间，则无需迭代，因为这是一个对象。只需引用您正在比较的属性对象引用即可。

if(operatingHours.Monday.string === operatingHours.Saturday.string){
    //-- Do your stuff
}

【讨论】：