在 PHP 中从 mysql 结果中搜索一个表

Question

如何将查询中的搜索结果放入表中，然后选择一个条目以更新表单中的详细信息？

所以我有我的表格：姓名、地址、电话、邮政编码、电子邮件等。

我有一个搜索邮政编码的搜索查询。

我有一个结果列表，然后我想选择一个（选择按钮或类似的东西）并将其余信息填回我的表单。

表格是这样的

<td><form action="searchresults.php" method="post" name="form1" id="form1">
  <table width="100%" border="0" cellspacing="1" cellpadding="3">
    <tr>
      <td colspan="3"><strong>Find a Active Physio</strong></td>
    </tr>
    <tr>
      <td width="100">Physio Reference</td>
      <td width="301"><input name="PhysioReference" type="text" id="PhysioReference" /></td>
    </tr>
    <tr>
      <td>Name of Physio</td>
      <td><input name="Physio" type="text" id="Physio" /></td>
    </tr>
    <tr>
      <td>Contact Number</td>
      <td><input name="Number" type="text" id="Number" /></td>
    </tr>
    <tr>
      <td>Address</td>
      <td><input name="PhysiosAddress" type="text" id="PhysiosAddress" /></td>
    </tr>
    <tr>
      <td>Postcode</td>
      <td><input name="postcode" value="" type="text" id="postcode" />
        <input type="submit" name="submit" value="Search" /></td>
    </tr>
    <tr>
      <td>Physios Email</td>
      <td><input name="PhysiosEmail" type="text" id="PhysiosEmail" /></td>
    </tr>
    <tr>
      <td colspan="3" align="center">&nbsp;</td>
    </tr>
  </table>
</form></td>

这样的搜索结果（需要把它们放到表格中）

<?php

require_once('auth.php');

$host=""; // Host name 
$username=""; // Mysql username
$password=""; // Mysql password 
$db_name=""; // Database name 
$tbl_name="Physio"; // Table name 

 // Connect to server and select database.
   mysql_connect($host, $username, $password)or die("cannot connect"); 
   mysql_select_db($db_name)or die("cannot select DB");

    if(!isset($_POST['postcode'])) {
      header ("location:index.php");
     } 
     echo "<p> Results </p>" ;
 $search_sql = "SELECT * FROM `Physio` WHERE Postcode like '%" . $_POST['postcode'] . "%'";
 $search_query = mysql_query($search_sql);

    while ($search_rs = mysql_fetch_array($search_query))
    {
   echo $search_rs['Reference'] . '<br>';
   echo $search_rs['Physio'] . '<br>';
   echo $search_rs['Postcode'] . '<br>';
   echo $search_rs['Line1'] . '<br>';
   echo $search_rs['Tel'] . '<br>';
}
if (!empty($search_rs))
{
echo "<p> Results Found </p>" ;
}
else
{
echo "<p> No Results Found </p>" ;
}

   ?>

Answer 1

试试这个

  echo"<table><tr>" ;
  echo '<th>Reference</th><th>Physio</th><th>Postcode</th><th>Line1</th><th>Tel</th></tr>';
    while ($search_rs = mysql_fetch_array($search_query))
         {
         echo '<tr>';
         echo "<td>".$search_rs['Reference'] . "</td>";
         echo "<td>".$search_rs['Physio'] . "</td>";
         echo "<td>".$search_rs['Postcode'] . "</td>";
         echo "<td>".$search_rs['Line1'] . "</td>";
         echo "<td>".$search_rs['Tel'] . "</td>";
         echo '</tr>';
         }
  echo '</table>';

用于学习用php构建html表格

read this

    echo "<td><a href="url">".$search_rs['Reference'] . "</a></td>";