如何获取每个上传文件的 URL 并通过电子邮件发送？

Question

概述： 我有一个包含 5 个文件上传字段的表单。一个 php 脚本处理数据并发送 2 封电子邮件（一封给管理员，一封确认回执给用户）并将数据附加到服务器上的 .csv 文件中。

问题： 如何将上传文件的 URL 放入可用于填充电子邮件和 .csv 文件的变量中。

一切都很好，除了我需要一个指向电子邮件和 .csv 文件中包含的每个上传文件的链接。经过几天的尝试，我似乎无法弄清楚那部分。

简化的 HTML 表单：

<HTML><head><title>MultiFile Upload and Send Email</title></head><body>         
<form method='post' action='php/multiUploadTestProcess.php' multipart='' enctype='multipart/form-data'>
    <label for ='exhName'>Exhibitor Name:</label>
    <input type='text' name='exhName' multiple class='form-control'><br><br>
    Select File 1: <input type='file' name='img[]' multiple class='form-control' size='10'><br><br>
    Select File 2: <input type='file' name='img[]' multiple class='form-control' size='10'><br><br>
    Select File 3: <input type='file' name='img[]' multiple class='form-control' size='10'><br><br>
    Select File 4: <input type='file' name='img[]' multiple class='form-control' size='10'><br><br>
    Select File 5: <input type='file' name='img[]' multiple class='form-control' size='10'><br><br>
    <input type='submit' value='upload'>
</form>

PHP：注意：我已删除所有验证/清理、删除 .csv 附加文件和第二封电子邮件提交。我假设一旦我们可以获取一封电子邮件的链接，其余部分将几乎相同。

<?php
$exhName = $_POST['exhName'];
$exhNameNoSpace = str_replace(" ","-", $exhName);
$img = $_FILES['img'];
$to = 'DESTINATION-EMAIL@DOMAIN.com';
$subject = 'New File Uploads';
$email = 'ReplyYToEMAIL@DOMAIN.com';

if(!empty($img))
{
    /* reArrayFiles changes the array pattern for PHP's $_FILES (see function at end)  */
    $img_desc = reArrayFiles($img);
    print_r($img_desc);

    /* RENAME EACH FILE to current date, exhibitor name w/o spaces, and random integer string (ensuring no file overwrites). Then MOVE FILE to uploads */
    foreach($img_desc as $val)
    {
        $newname = date('m-d-Y',time()).'-'.$exhNameNoSpace.'-'.mt_rand().'.jpg';
        move_uploaded_file($val['tmp_name'],'../uploads/'.$newname);
        /* THIS FOLLOWING LINE WAS MY ATTEMPT AT GETTING A LINK TO EACH UPLOADED FILE BUT IS NOT WORKING. AND THE VARIABLE $newname HERE IS ADDING A NEW RANDOM INT TO THE FILENAME - NOT THE ONE THE FILE WAS SAVED WITH. */
        $filePath = '**Full Path To Directory**'.$newname;
    }
    /* SEND EMAIL TO ADMIN */
            $emailText = "=============================================\nYou have a new Market Place Application\n".
            "Here are the details:\n=============================================\n\n Exhibitor Name: $exhName \n\n Upload File 1: $filePath \n\n Upload File 2: $filePath \n\n ###";

            // All the neccessary headers for the email.
            $headers = array('Content-Type: text/plain; charset="UTF-8";',
                'From: ' . $email,
                'Reply-To: ' . $email,
                'Return-Path: ' . $email,
            );
            $emailText = wordwrap($emailText, 70);
            // Send email
            mail($to, $subject, $emailText, implode("\n", $headers));
    /* END SEND EMAIL TO ADMIN */
}
function reArrayFiles($file)
{
    $file_ary = array();
    $file_count = count($file['name']);
    $file_key = array_keys($file);

    for($i=0;$i<$file_count;$i++)
    {
        foreach($file_key as $val)
        {
            $file_ary[$i][$val] = $file[$val][$i];
        }
    }
    return $file_ary;
}   
?>

非常感谢您的帮助！

Answer 1

1. 如果您想将文件附加到您的电子邮件中，您可能需要服务器上的完整路径而不是外部 URL。查看realpath PHP 函数并尝试将保存文件的路径包装到此函数调用中，使其类似于：

   $newname = date('m-d-Y',time()).'-'.$exhNameNoSpace.'-'.mt_rand().'.jpg';
   move_uploaded_file($val['tmp_name'],'../uploads/'.$newname);
   /* THIS FOLLOWING LINE WAS MY ATTEMPT AT GETTING A LINK TO EACH UPLOADED FILE BUT IS NOT WORKING. AND THE VARIABLE $newname HERE IS ADDING A NEW RANDOM INT TO THE FILENAME - NOT THE ONE THE FILE WAS SAVED WITH. */
   $filePath = realpath('../uploads/'.$newname);
   

$filepath 之后应该包含服务器上上传文件的完整路径。

1. 如果您希望将带有外部 URL 的链接添加到您的邮件中，您确实需要完整的 URL，但这取决于域名和上传文件夹相对于您的域的根 (/) 的位置。它应该类似于http://example.com/uploads/11-16-2018-name-6534.jpg，您可以通过通过浏览器测试对生成的文件名的访问来确定它，假设您的上传文件夹可以通过网络服务器访问。确定 URL 后，您可以将域和路径保存到配置文件中，或者您可以检查 $_SERVER['SERVER_NAME'] 是否包含域名并将其附加到路径中。

为了在电子邮件文本中使用 URL，您需要修改您的代码，例如：

$emailText = "=============================================\nYou have a new Market Place Application\nHere are the details:\n=============================================\n\n Exhibitor Name: $exhName \n\n ";
$i = 1;
foreach($img_desc as $val)
{
    $newname = date('m-d-Y',time()).'-'.$exhNameNoSpace.'-'.mt_rand().'.jpg';
    move_uploaded_file($val['tmp_name'],'../uploads/'.$newname);
    /* THIS FOLLOWING LINE WAS MY ATTEMPT AT GETTING A LINK TO EACH UPLOADED FILE BUT IS NOT WORKING. AND THE VARIABLE $newname HERE IS ADDING A NEW RANDOM INT TO THE FILENAME - NOT THE ONE THE FILE WAS SAVED WITH. */
    $filePath = '**Full Path To Directory**'.$newname;
    $emailText .= "Upload File " . $i . ": " . $filePath . "\n\n";
    $i++;
}

// All the neccessary headers for the email.
$headers = array('Content-Type: text/plain; charset="UTF-8";',
            'From: ' . $email,
            'Reply-To: ' . $email,
            'Return-Path: ' . $email,
);
$emailText = wordwrap($emailText, 70);
// Send email
mail($to, $subject, $emailText, implode("\n", $headers));