过滤 JSON 响应

Question

我收到了来自 xhr 的回复，如下所示：

{
    "9994921432": {
        "name": "name 1",
        "ownerid": "543624"
    },
    "9979509360": {
        "name": "some name",
        "ownerid": "765875"
    },
    "9979524523": {
        "name": "some other name",
        "ownerid": "215654"
    },
    "9979524523": {
        "name": "some name",
        "ownerid": "65893"
    }
}

我试图根据“名称”的值过滤它，如果可能的话，使用“单线”（我不能使用 jQuery）。我正在测试这样的东西：

var response = '{ "9994921432": { "name": "the name", "ownerid": "543624" }, "9979509360": { "name": "some name", "ownerid": "765875" }, "9979524523": { "name": "some name", "ownerid": "215654" }, "9979524523": { "name": "some other name", "ownerid": "65893" } }';
var json = JSON.parse( '[' + response + ']' );
var filtered = json.filter( function ( item ) { return item.name == 'some name' } );
console.log( filtered );

但是filtered 是空的。

我怎样才能得到像json 这样的对象，但只包含name == "some name" 的对象？

Answer 1

尝试如下。您必须遍历对象而不是数组。

var response = '{ "9994921432": { "name": "the name", "ownerid": "543624" }, "9979509360": { "name": "some name", "ownerid": "765875" }, "9979524523": { "name": "some name", "ownerid": "215654" }, "9979524524": { "name": "some other name", "ownerid": "65893" } }';
var json = [];
var resObj = JSON.parse(response);
for(var key in resObj) {
  if(resObj[key].name == 'some name') {
    json.push(resObj[key]);
  }
}

console.log(json);

Answer 2

用这段代码解决了：

var response = '{ "9994921432": { "name": "the name", "ownerid": "543624" }, "9979509360": { "name": "some name", "ownerid": "765875" }, "9979524523": { "name": "some name", "ownerid": "215654" }, "45756745675": { "name": "some name", "ownerid": "65893" } }';

var json = JSON.parse( response );
var filtered = {};

Object.keys( json ).forEach( function( key ) {
    if( json[key].name == "some name" ) {
        filtered[key] = json[key];
    }
});

console.log( filtered );

不是我想要的单线，但能胜任。