【发布时间】:2015-10-12 12:40:36
【问题描述】:
我已经制作了这个 JSON 菜单,但在其父 LI 中获取子菜单 UL 时遇到了困难 - 有人知道我需要在这里调整什么吗?
JS:
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<script type="text/javascript">
// lets do some JSON magic and make a menu!
JSON = {
"menu":[
{
"id":"contact",
"leaf":true,
"description":"Contact Us",
"link":"",
"content":"contactUs.html",
"cssClass":"static-content",
"menu":null
},
{
"id":"rules",
"leaf":false,
"description":"Sports Betting Rules",
"link":"",
"content":"",
"cssClass":"",
"menu":[
{
"id":"types",
"leaf":true,
"description":"Wager Types",
"link":"",
"content":"wagerTypes.html",
"cssClass":"static-content wager-types",
"menu":null
},
{
"id":"odds",
"leaf":true,
"description":"Odds & Lines",
"link":"",
"content":"oddsAndLines.html",
"cssClass":"static-content",
"menu":null
},
{
"id":"policies",
"leaf":true,
"description":"Rules & Policies",
"link":"",
"content":"rulesAndPolicies.html",
"cssClass":"static-content rules-policies",
"menu":null
},
{
"id":"bonuses",
"leaf":true,
"description":"Sports Bonuses",
"link":"",
"content":"sportsBonuses.html",
"cssClass":"static-content",
"menu":null
}
]
},
{
"id":"conditions",
"leaf":false,
"description":"Terms & Conditions",
"link":"",
"content":"",
"cssClass":"",
"menu":[
{
"id":"termsOfService",
"leaf":true,
"description":"Terms of Service",
"link":"",
"content":"termsOfService.html",
"cssClass":"static-content",
"menu":null
},
{
"id":"privacy",
"leaf":true,
"description":"Privacy Policy",
"link":"",
"content":"privacy.html",
"cssClass":"static-content",
"menu":null
}
]
},
{
"id":"view",
"leaf":true,
"description":"View in: Mobile | Full Site",
"link":"",
"content":"view.html",
"cssClass":"static-content",
"menu":null
}
]
}
$(document).ready(function () {
function buildMenu(ul, menu) {
for (var i = 0; i < menu.length; i++) {
var li = $(ul).append('<li id="'+menu[i].id+'" class="'+menu[i].leaf+' '+menu[i].cssClass+'"><a href="'+menu[i].link+'">'+menu[i].content+'</a></li>');
if (menu[i].menu!=null) {
var subul=$('<ul id="submenu-'+menu[i].id+'"></ul>');
$(li).append(subul);
buildMenu($(subul), menu[i].menu);
}
}
}
var menu = $(".main-menu");
buildMenu(menu, JSON.menu);
});
</script>
<div class="main-menu"></div>
【问题讨论】:
-
你能创建一个jsfiddle吗,jsfiddle.net
标签: javascript jquery html css json