【发布时间】:2017-08-31 03:39:30
【问题描述】:
我想问....为什么我的下拉菜单不能显示文字?我确保我的代码是正确的......但我不能显示任何文字......我真的很困惑...... 这是我的单选按钮图片:
这里是我在 view.php 中的 html 代码 .........
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
<div class="dropdown dropdown-full-width dropdown-category">
<button class="btn btn-default dropdown-toggle" type="button" data-toggle="dropdown" >
<span class="name">
<span id="category-select">- -
@foreach($categoriesid as $kategori)
{{ $kategori->name}} -
@endforeach
-</span>
</span>
<span class="caret"></span>
</button>
<div class="dropdown-menu row">
<div class="col-md-4">
<li><strong>By {{ $category[1] }}</strong></li>
@foreach($category1 as $occasions)
@php
$checked = false;
foreach ($categoriesid as $d) {
if($d->id == $occasions->id) $checked=true;
}
@endphp
<li>
<div class="checkbox">
@if($checked)
<label><input type="radio" name="category['occasions']" class="category-radio" value="{{ $occasions->id }}" checked="checked"> {{ $occasions->name }}</label>
@else
<label><input type="radio" name="category['occasions']" class="category-radio" value="{{ $occasions->id }}"> {{ $occasions->name }}</label>
@endif
</div>
</li>
@endforeach
</div>
<div class="col-md-4">
<li><strong>By {{ $category[2] }}</strong></li>
@foreach($category2 as $types)
@php
$checked = false;
foreach ($categoriesid as $d) {
if($d->id == $types->id) $checked=true;
}
@endphp
<li>
<div class="checkbox">
@if($checked)
<label><input type="radio" name="category['types']" class="category-radio" value="{{ $types->id }}" checked="checked"> {{ $types->name }}</label>
@else
<label><input type="radio" name="category['types']" class="category-radio" value="{{ $types->id }}"> {{ $types->name }}</label>
@endif
</div>
</li>
@endforeach
</div>
<div class="col-md-4">
<li><strong>By {{ $category[3] }}</strong></li>
@foreach($category3 as $flowers)
@php
$checked = false;
foreach ($categoriesid as $d) {
if($d->id == $flowers->id) $checked=true;
}
@endphp
<li>
<div class="checkbox">
@if($checked)
<label><input type="radio" name="category['flowers']" class="category-radio" value="{{ $flowers->id }}" checked="checked"> {{ $flowers->name }}</label>
@else
<label><input type="radio" name="category['flowers']" class="category-radio" value="{{ $flowers->id }}"> {{ $flowers->name }}</label>
@endif
</div>
</li>
@endforeach
</div>
</div>
</div>
这里是我的 javascript 代码.......
$(function(){
$('input[type="radio"]').click(function(){
var $radio = $(this);
var name = $(this).prop("name");
// if else for checked true and false
if ($radio.data('waschecked') == true)
{
$radio.prop('checked', false);
$radio.data('waschecked', false);
$('#category-select').text('');
}
else{
$radio.data('waschecked', true);
$(`input[name=${name}]:not(:checked)`).data('waschecked', false);
$('#category-select').text(txt).trim();
}
let output = [];
var txt;
$('input[type="radio"]:checked').each( function() {
txt = $(this).parent().text().trim();
output.push(txt);
});
$('#category-select').text(output.join(' - '));
});
});
请帮助我了解这个 javascript...因为我是 javascript 的新手.....
【问题讨论】:
-
你能发布渲染的 HTML 吗?从浏览器检查 HTML 代码是什么?
-
@FaizFurios52 你的
ul在哪里?你刚从div开始,类名为dropdown,然后是li,你缺少ul。 -
尝试在浏览器控制台中检查
$(this).parent().text().trim();的值以查找选定的单选按钮。
标签: javascript php jquery html laravel-5.3