回显 JSON 编码数据答案

【问题标题】：Echo JSON encoded data回显 JSON 编码数据
【发布时间】：2017-04-19 06:10:35
【问题描述】：

我正在使用 Codeigniter RESTful API 根据输入从数据库中获取数据。现在我想改变以不同方式显示我的 json 输出的方式。

代码：

function categoryskills_get()
{
    $category = $this->get('category');
    $skills = $this->Users_model->categoryskills($category);
    if($skills != FALSE)
    {
        $sub_cat = 0;
        foreach($skills['skills'] as $row)
        {
            $data[$skills['cat']][]['sub_category'] = $row['sub_cat'];
            $data[$skills['cat']][]['skills'] = $row['s_name'];
        }
        $this->set_response($data, REST_Controller::HTTP_OK);
    }else{
        $response["error"] = TRUE;
        $response["status"] = '404';
        $response["error_msg"] = "Category not found!";
        $this->set_response($response, REST_Controller::HTTP_NOT_FOUND);
    }
}

上面的代码是我的 http 请求的控制器。

电流输出：

{
"Consultants": [
    {
        "sub_category": "Consultants"
    },
    {
        "skills": "Career Counsellor, Creative Consultant,Digital Consultant"
    },
    {
        "sub_category": "Accounting"
    },
    {
        "skills": "Accountant,Auditor,Tax Specialist"
    }

 ]
}

预期输出：

{
"Consultants": [
    {
        "sub_category": "Consultants",
        "skills": "Career Counsellor,Creative Consultant,Digital Consultant"
    },
    {
     .....
    }
 ]
}

【问题讨论】：

标签： json codeigniter api encoding

【解决方案1】：

function categoryskills_get()
{
    $category = $this->get('category');
    $skills = $this->Users_model->categoryskills($category);
    if($skills != FALSE)
    {
        $sub_cat = 0;
        foreach($skills['skills'] as $key=>$row)
        {
            $data[$skills['cat']][$key]['sub_category'] = $row['sub_cat'];
            $data[$skills['cat']][$key]['skills'] = $row['s_name'];
        }
        $this->set_response($data, REST_Controller::HTTP_OK);
    }else{
        $response["error"] = TRUE;
        $response["status"] = '404';
        $response["error_msg"] = "Category not found!";
        $this->set_response($response, REST_Controller::HTTP_NOT_FOUND);
    }
}

使用 foreach 作为键、值并将 $key 放入这样的数组中 $data[$skills['cat']][$key]['sub_category'] 你会得到想要的输出

【讨论】：

【解决方案2】：

只需为 sub_cat 和技能制作单独的临时数组

$category = $this->get('category');
    $skills = $this->Users_model->categoryskills($category);
    $data = array();//create an empty array
    if($skills != FALSE)
    {
        $sub_cat = 0;
        foreach($skills['skills'] as $row)
        {
            $arr['sub_category'] = $row['sub_cat'];
            $arr['skills'] = $row['s_name'];//makes an $arr array

            $data[$skills['cat']][] = $arr;  //and after that add it to                        main array
        }
        $this->set_response($data, REST_Controller::HTTP_OK);
    }else{
        $response["error"] = TRUE;
        $response["status"] = '404';
        $response["error_msg"] = "Category not found!";
        $this->set_response($response, REST_Controller::HTTP_NOT_FOUND);
    }
}

【讨论】：

【解决方案3】：

function categoryskills_get()
{
    $category = $this->get('category');
    $skills = $this->Users_model->categoryskills($category);
    if($skills != FALSE)
    {
        $sub_cat = 0;
        foreach($skills['skills'] as $row)
        {
            $data[$skills['cat']][] = array('sub_category'=>$row['sub_cat'],'skills'=>$row['s_name']);
        }
        $this->set_response($data, REST_Controller::HTTP_OK);
    }else{
        $response["error"] = TRUE;
        $response["status"] = '404';
        $response["error_msg"] = "Category not found!";
        $this->set_response($response, REST_Controller::HTTP_NOT_FOUND);
    }
}

【讨论】：

【解决方案4】：

使用array_push() 方法如下：

$category = $this->get('category');
    $skills = $this->Users_model->categoryskills($category);
    $data = array();//create an empty array
    if($skills != FALSE)
    {
        $sub_cat = 0;
        foreach($skills['skills'] as $row)
        {
            $arr['sub_category'] = $row['sub_cat'];
            $arr['skills'] = $row['s_name'];//makes an $arr array
            array_push($data[$skills['cat']], $arr);//push array
        }
        $this->set_response($data, REST_Controller::HTTP_OK);
    }else{
        $response["error"] = TRUE;
        $response["status"] = '404';
        $response["error_msg"] = "Category not found!";
        $this->set_response($response, REST_Controller::HTTP_NOT_FOUND);
    }
}

【讨论】：