【发布时间】:2018-09-15 13:25:21
【问题描述】:
我一直坚持通过 Ajax 从数据库获取结果。 id="view_errorcode" 有效,但 id="view_vlokasi" 无效,仅显示 UNDEFINED。谁能告诉我在我的代码中做错了什么?
$('#showdata').on('click', '.item-info', function(){
var tid = $(this).attr('data');
$.ajax({
type: 'ajax',
method: 'get',
url: '<?php echo base_url() ?>RepeatProblem/infoReprob',
data: {tid:tid},
async: false,
dataType: 'json',
success: function(data){
var vlokasi = '<span style="font-size:22px;color:green">'+data.lokasi+'</span>';
var html = '';
var i;
for(i=0; i<data.length; i++){
html +='<p style="font-size:18px;color:black"><i class="fa fa-check"></i> '+data[i].lokasi+' '+data[i].updated_at+'<br>'+data[i].ketprob+'</p>';
}
$('#infoModal').modal('show');
$('#view_lokasi').html(vlokasi); // showing UNDEFINED
$('#view_errorcode').html(html); // Working
},
error: function(){
alert('Gagal Info Kode Error!');
}
});
});
ajax调用返回如下json
[{"tid":"550250","ketprob":"1","updated_at":"15-09-2018 19:39","lokasi":"ERA MART TENGKAWANG"},{"tid":"550250","ketprob":"2","updated_at":"15-09-2018 19:39","lokasi":"ERA MART TENGKAWANG"},{"tid":"550250","ketprob":"3","updated_at":"15-09-2018 19:39","lokasi":"ERA MART TENGKAWANG"},{"tid":"550250","ketprob":"4","updated_at":"15-09-2018 19:37","lokasi":"ERA MART TENGKAWANG"}]
【问题讨论】:
-
谁能帮我解决这个问题,为什么“data.lokasi”显示为 UNDEFINED 而“data[i].lokasi”有效?请
-
因为
data显然是一个数组。
标签: javascript ajax codeigniter undefined codeigniter-3