【发布时间】:2017-03-18 06:40:12
【问题描述】:
how to validation using javascript popup model in codeigniter
登录代码如下所示
登录页面中显示的以下代码我尝试了很多次验证方法,但我没有得到
<form id="register-form" action="<?php echo base_url(); ?>Index.php/Login_cntrl/login" method="POST" >
<div class="field-wrap">
<label class="view-label">Email Address</label>
<input type="email" placeholder="Email Address" name="email" id="email" class="input-control" value=""/>
</div>
<div class="field-wrap">
<input type="password" placeholder="Password" name="password" id="password" value="" />
<a href="javascript:void(0)" class="btn btn-link btn-nobg" id="btn-show-forgot" >Forgot ?</a>
</div>
<div class="field-wrap">
<button type="submit" class="btn btn-submit" name="ulogin" id="ulogin" value="ulogin" >Login</button>
</div>
<div class="field-wrap">
<a href="javascript:void(0)" class="btn btn-link btn-nobg" id="btn-show-signup">NEW User? Sign up</a>
</div>
</form>
validation.js
<script src="//ajax.aspnetcdn.com/ajax/jquery.validate/1.9/jquery.validate.min.js"></script>
<script type="text/javascript" src="<?php echo base_url(); ?>js/validation.js"></script>
$(function() {
$("#register-form").validate({
// Specify the validation rules
rules: {
email: {
required: true,
email: true
},
password: {
required: true,
maxlength: 8
}
},
// Specify the validation error messages
messages: {
email: "Please enter your email",
password: "Please enter your password",
},
submitHandler: function(form) {
form.ulogin();
}
});
});
【问题讨论】:
-
将您尝试的代码添加到问题中
-
刚才我添加js文件代码过一遍
-
代码不工作,我知道原因吗
标签: javascript html css codeigniter